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3 years ago

Which does not represent two equivalent expressions 51 MAFS.6.EE.1.1 Which does not represent two equivalent expressions?

Mathematics

1 answer:

Vinvika [58]3 years ago

6 0

Answer: B

Explanation: 4 times 3 is equivalent to 12 and the question was asking for exponents. A has 3 multiplied by itself 3 times so that is correct. C has 6 multiplying itself 4 times so that would be correct. D has 5 Multiplying itself 2 times so that would be correct. The only one that does not represent equivalency would be B.

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so if i have 2 brands of fruit snacks and one of them costs 48.60 and the other brand is 40.15 which brand cost less per pound

Lynna [10]

Answer: 40.15

Step-by-step explanation: 40.15 IS LESS THEN 48.60

4 0

3 years ago

4. Name the first five terms of the arithmetic sequence. a1 = -35, d=4

eduard

Answer:

Step-by-step explanation:

We first have to write the equation for the sequence, then finding the first five terms will be easy. Follow the formatting:

$a_n=a_1+d(n-1)$ and we are given enough info to fill in:

$a_n=-35+4(n-1)$ and

$a_n=-35+4n-4$ and

$a_n=-39+4n$ or in linear format:

$a_n=4n-39$ where n is the position of the number in the sequence. We already know the first term is -35.

The second term:

$a_2=4(2)-39$ so

$a_2=8-39$ and

$a_2=-31$

The third term:

$a_3=4(3)-39$ and

$a_3=12-39$ so

$a_3=-27$ and we could go on like this forever, but the nice thing about this is when we know the difference all we have to do is add it to each number to get to the next number.

That means that the fourth term will be -27 + 4 which is -23.

The fifth term then will be -23 + 4 which is -19. You can check yourself by filling in a 5 for n in the equation and solving:

$a_5=4(5)-39$ and

$a_5=20-39$ so

$a_5=-19$

7 0

3 years ago

Use inductive reasoning to find the next term in this sequence 2,3,5,9,17. Then explain the rule for the pattern.

NISA [10]

We have been given the sequence 2,3,5,9,17.

We can write the terms of this sequence as

$2=2^0+1\\
3=2^1+1\\
5=2^2+1\\
9=2^3+1\\
17=2^4+1\\$

From the above term we can see that for the first term we take exponent 0 on 2 and then add 1 .

For second term we take exponent 1 on 2 and then add 1 .

For third term we take exponent 2 on 2 and then add 1 .

Using this fact for the next term of the sequence i.e. 6th term, we can take exponent 5 on 2 and then add 1 .

Therefore, next term of the sequence is given by

$2^5+1\\
=32+1\\
=33$

Therefore, the next term is 33.

Using the above facts, the pattern is given by

$a_n=2^{n-1}+1$

7 0

3 years ago

It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando

notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, $\overline x_1$ = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, $\overline x_2$ = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀: $\overline x_1$ = $\overline x_2$

The alternative hypothesis, Hₐ: $\overline x_1$ ≠ $\overline x_2$

The pooled variance, $S_p^2$ , is given as follows;

$S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}$

Therefore, we have;

$S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682$

The test statistic is given as follows;

$t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}$

Therefore, we have;

$t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176$

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0

3 years ago

Iliana was part of a group that was working on changing 0.4 repeated to a fraction. Each member of the group had a different ans

amm1812

$\bf 0.444444444\overline{4}\impliedby \textit{and keeps on going}\\\\
-------------------------------\\\\
\textit{let's say }\boxed{x=0.444444444\overline{4}}\quad \textit{ thus }10\cdot x=4.44444444\overline{4}
\\\\\\
\textit{wait a minute! }4.44444444\overline{4}\textit{ is really just }4+0.444444444\overline{4}$

$\bf \textit{but we know }x=0.444444444\overline{4} \textit{ so then }4+0.444444444\overline{4}=\boxed{4+x}
\\\\\\
\textit{wait a second! }10\cdot x\implies 10x=4.444444444\overline{4}=4+x
\\\\\\
thus\qquad 10x=4+x\implies 10x-x=4\implies 9x=4\implies \boxed{x=\cfrac{4}{9}}$

you can check in your calculator.

anyhow, to get the "recurring decimal to fraction", you start by setting to some variable, "x" in this case, then move the repeating part to the left of the point by multiplying it by some power of 10, and then do the equating.

3 0

4 years ago

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