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jok3333 [9.3K]
3 years ago
15

This is just algebra need some help 10 pts each, will give brainliest

Mathematics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

\huge \boxed{ \boxed{z = 3}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • equation
  • PEMDAS
<h3>let's solve:</h3>
  1. \sf simplify \: substraction :  \\  \frac{3}{ \frac{z - 2}{z} }  = 3z
  2. \sf simplify \: complex \: fractio n : \\  \frac{3z}{z - 2}  = 3z
  3. \sf cross \: multiplication :  \\ 3z = 3z(z - 2)
  4. \sf divide \: both \: sides \: by \:  3z :  \\  \frac{3z}{3z} =   \frac{3z(z - 2)}{3z} \\ 1 = z - 2
  5. \sf add \: 2 \: to \: bot h  \: sides :  \\  z - 2 +  2 = 1 + 2 \\ \therefore \: z = 3

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1) At a diner, the cost for a specialty waffle and a hashbrown is $9.50. The cost for 2 specialty
klemol [59]

9514 1404 393

Answer:

  • waffle $8
  • hashbrowns $1.50

Step-by-step explanation:

Using w and h for the costs of a waffle and hashbrowns, respectively, we can write the equations for the purchase amounts as ...

  w + h = 9.50

  2w + 3h = 20.50

Subtracting twice the first equation from the second gives ...

  (2w +3h) -2(w +h) = (20.50) -2(9.50)

  h = 1.50 . . . . . . simplify

  w = 9.50 -h = 8.00 . . . . . find w using the first equation

The cost of a waffle is $8.00; the cost of hashbrowns is $1.50.

4 0
3 years ago
What are the intercepts of the line?
Schach [20]
To solve your X int you substitute 0 for y.

X int-
-5x+9(0)=-18
-5x=-18
X= 18/5 and the coordínate is (18/5,0)

Then to solve for y int you substitute 0 for x.

-5(0)+9y=-18
9y=-18
Y= -2 and the coordinate is (0,-2)
3 0
3 years ago
Select all of the values of
omeli [17]

Answer:

gmkyhmfnggnjggfbvmhfjxxjyyjyjhchhfxg

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP IM BEHIND AND SCHOOL IS OUT IN 2 DAYS
Alexxx [7]

Answer: #1 his school is out

Step-by-step explanation: #2 bcuz all sides equal to 66cm.

Please mark me brainlest.✌✌

5 0
3 years ago
Katya made another set of dolls. In the new set, the largest doll has a diameter of 8.75 cm and a height of 15.6 cm. Is this a d
Natali5045456 [20]

<em>Complete Question:</em>

<em>Katya creates handmade sets of dolls, which is sold to craft and souvenir stores. The first set of dolls has a middle diameter of 7cm and a height of 12cm.</em>

<em>Katya made another set of dolls. In the new set, the largest doll has a diameter of 8.75 cm and a height of 15.6 cm. Is this a dilation of the first set of dolls? </em>

<em></em>

Answer:

The new set is not a dilation of the first set

Step-by-step explanation:

Given

First Set:

Height = 12cm

Diameter = 7cm

New Set:

Height = 15.6cm

Diameter = 8.75cm

Required

Determine if the new set is a dilation of the second

To do this, we pass through the following steps:

1. Divide the height of the first set by the new set

2. Divide the diameter of the first set by the new set

3. Result in (1) and (2) must be equal if the new set is a dilation of the first set

Following the steps above:

(1)

Height\ Ratio = \frac{H_2}{H_1}

Height\ Ratio = \frac{15.6}{12}

Height\ Ratio = 1.3

(2)

Diameter\ Ratio = \frac{D_2}{D_1}

Diameter\ Ratio = \frac{8.75}{7}

Diameter\ Ratio = 1.25

(3) Make comparison

The ratio in (1) does not equal the ratio in (2)

i.e.

1.3 \neq 1.25

<em>Hence, the new set is not a dilation of the first set</em>

7 0
3 years ago
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