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Andreyy89
2 years ago
15

C= ( F - 32) / 1.8 86 F = ?

Chemistry
1 answer:
egoroff_w [7]2 years ago
7 0

<h3>⇒c =  \frac{f - 32}{1.8}</h3><h3>⇒c =  \frac{86 - 32}{1.8}</h3><h3>⇒c =  \frac{54}{1.8}</h3><h3>⇒c = 30</h3>

<em>Hence</em><em>,</em><em> </em><em>84</em><em>°</em><em>F</em><em> </em><em>is</em><em> </em><em>30</em><em>°</em><em>C</em><em> </em><em>in</em><em> </em><em>Celsius</em><em>.</em><em>.</em>

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The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abb
Talja [164]

The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. 262 grams of sucrose are needed to make 655 mL of a 40.0% (w/v) sucrose solution

<h3>Define Solute</h3>

A solute is a material that dissolves in a solution. The amount of solvent present in fluid solutions is greater than the amount of solute. The two most common examples of solutions in daily life are salt and water. Salt is the solute because it dissolves in water.

<h3>forms of ratios for product concentration or yield:-</h3>
  • w/v:- Weight by volume or weight per volume are the terms used. Any solid compound's concentration in a liquid can be calculated using it. It is measurable in gm/ml.
  • Weight by weight ratio is referred to as w/w.It is employed to determine the final yield of the compound obtained from the starting compound. as in —mg/—gm.

       It provides the real yield of the substance or item.

  • Volume/volume. It is used to specify a liquid's composition or percent in a liquid compound.

using w/v we can calculate the weight of sucrose:-

40.0% means 40 g sucrose/ 100 g solution

40.0g sucrose x (655/100)=grams of sucrose

262  grams of sucrose are needed to make 655 mL of a 40.0% (w/v) sucrose solution.

Learn more about Solute here:-

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6 0
2 years ago
A goldsmith melts 12.4 grams of gold to make a ring. The temperature of the gold rises from 26°C to 1064°C, and then the gold me
DiKsa [7]

Problem One

You will use both m * c * deltaT and H = m * heat of fusion.

Givens

m = 12.4 grams

c = 0.1291

t1 = 26oC

t2 = 1204

heat of fusion (H_f) = 63.5 J/grams.

Equation

H = m * c * deltaT + m * H_f

Solution

H = 12.4 * 0.1291 * (1063 - 26) + 12.4 * 63.5

H = 1660.1 + 787.4

H = 2447.5 or 2447.47 is the exact answer. I have to leave the rounding to you. I have no idea where to round it although I suspect 2450 would be right for 3 sig digs.

Problem Two

Formula and Givens

t1 = 14.5

t2 = 50.0

E = 5680

c = 4.186

m = ??

E = m c * deltaT

Solution

5680 = m * 4.186 * (50 - 14.5)

5680 = m * 4.186 * (35.5)

5680 = m * 148.603 * m

m = 5680 / 148.603

m = 38.22 grams That isn't very much. Be very sure you are working in joules. You'd leave that many grams in the kettle after drying it thoroughly.

m = 38.2 to 3 sig digs.

8 0
3 years ago
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Which of the following would heat up the quickest?
zysi [14]

Answer:

mercury( specific heat=0.140j/gc)

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3 years ago
Describe two ways in which a cell grows.
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There are two types of cell division: mitosis and meiosis. Most of the time when people refer to “cell division,” they mean mitosis, the process of making new body cells.

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2 years ago
Helpppppppppppppppp?
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Answer: A

Explanation:

6 0
3 years ago
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