Yes, the ones that make of the atom itself. The proton which is a positive charge which has most of the weight of the atom and is found in the nucleus. The neutron which weighs almost nothing has a neutral charge and is found in the nucleus with the protons. Lastly the electrons which have a negative charge and orbit the atom in the electron cloud around the nucleus and also weigh very little.
Answer:
The concentration of chloride ion is 2.887 M.
Explanation:
Here we have a combination BaCl₂ and AlCl₃
1 mole BaCl₂ can produce 2 moles chloride ions as follows;
BaCl₂ → Ba²⁺ + 2Cl⁻
Therefore;
0.554 mole BaCl₂ can produce 2×0.554 moles chloride ions;
1 mole AlCl₃ can produce 3 moles chloride ions as follows;
AlCl₃ → Al³⁺ + 3Cl⁻
Therefore;
0.593 mole AlCl₃ can produce 3×0.593 moles chloride ions
Total concentration of chloride ions = 2×0.554 + 3×0.593 = 2.887 moles of Cl⁻ in 2×16.8 ml solution
The concentration of Cl⁻ is 2.887 M
Answer:
3 water molecules
Explanation:
The molar ratio between CuSO₄ and H₂O needs to be calculated.
The mass of water that was removed by heating is calculated, then converted to moles. The molecular weight of water is 18.02g/mol.
(8.97 g - 6.57 g) = 2.22 g H₂O
(2.22 g)/(18.02g/mol) = 0.1232 mol H₂O
The moles of anhydrous copper sulfate are calculated. The molecular weight is 159.609 g/mol
(6.57 g)/(159.609 g/mol) = 0.04116 mol CuSO₄
Now the molar ratio between CuSO₄ and H₂O can be calculated:
0.1232 mol H₂O ÷ 0.04116 mol CuSO₄ = 3 H₂O / CuSO₄
Answer: 60.1K
Explanation:
Initial volume of gas V1 = 423.3mL
Initial temperature T1 = 49.2°C
Convert temperature in Celsius to Kelvin
( 49.2°C + 273 = 322.2K)
Final temperature T2 = ?
Final volume V2 = 79mL
According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.
Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2
423.3mL/322.2 = 79mL/T2
To get the value of T2, cross multiply
423.3mL x T2 = 322.2K x 79mL
423.3mL x T2 = 25453.8
T2 = (25453.8/423.3mL)
T2 = 60.1K
Thus, the new temperature of the gas is 60.1K
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