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Stels [109]
2 years ago
8

Evaluate the expression to find out how much she will pay if she drives 100 miles. 250 + 0.80m

Mathematics
1 answer:
zmey [24]2 years ago
7 0
We plug 100 miles into 0.80. 250 + 0.80(100) is 250 + 80. 250 + 80 is 330.
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(04.01 MC)
levacccp [35]

9514 1404 393

Answer:

  {(0, −5), (2, 9), (−3, −26)}

Step-by-step explanation:

You only need to try the first point in each set to eliminate the wrong answers.

a: 7(-5)-5 = -40 ≠ 0

b: 7(2)-5 = 9 ≠ 7

c: 7(0)-5 = -5 . . . matches given point

d: 7(1)-5 = 2 ≠ 3

The third choice is the correct one: {(0, −5), (2, 9), (−3, −26)}.

8 0
3 years ago
Square root of 25/16 - square rot of 36/25
muminat
Square root of 25/16 is 5/4
square root of 36/25 is 6/5

square root of 25/16 - square root of 36/25 = 5/4 - 6/5 = (25 - 24)/20 = 1/20
8 0
3 years ago
A basketball players hits 4 out of every 8 attempts at the basket. What is the ratio of baskets to number of attempts in its low
Juliette [100K]

Answer:

1:2

Step-by-step explanation:

Put the numbers as a ratio

4:8    Simplify this ratio by dividing both sides by 4

1:2     This is the ratio of baskets to number of attempts in its lowest terms

3 0
4 years ago
Read 2 more answers
The sum of the first number cubed and the second number is 500 and the product is a maximum.
soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

x^3+w=500

We can then express y as:

w=500-x^3

We can express their product as:

x(500-x^3)=500x-x^4

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}

Then we solve for the value of x where f'(x) = 0.

\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}

Then we use x = 5 to solve for the second number, w.

\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}

Therefore, the two numbers are 5 and 375.

3 0
1 year ago
Which problem is modeled on the number line?<br> 3+(-6)<br> -3+(6)<br> 3+6<br> -3+6
kramer

Answer:3+(-6)

Step-by-step explanation:

5 0
3 years ago
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