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PolarNik [594]
3 years ago
9

SOMEBODY PLEASE HELP ME!!!!!!! Solve each system of equations -3x + 3y =4 -x + y =3​

Mathematics
1 answer:
g100num [7]3 years ago
7 0
The 2 equations have no solution. If both are true, then

-3x + 3y = 4

-x + y = 4/3

Thus, 3 = 4/3, which is obviously wrong. Pls mark me as brainliest!
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The line represented by y = 3x − 2 and a line perpendicular to it intersect at R(3, 7). What is the equation of the perpendicula
laiz [17]

Answer:

y= -1/3(x) + 8

Step-by-step explanation:

slope of the 1st line = 3

slope of the line perpendicular to the first is its opposite reciprocal, so

slope of the 2nd line = -1/3

now we have a point and the slope of the perpendicular line, so we use the point slope formula to get:

y-7=-1/3(x-3)

y= -1/3(x) + 1 + 7

y= -1/3(x) + 8

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3 years ago
100 POINTS AND BRAINLIEST PLEASE HELP ASAP!!!
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Answer:

The answer is false.

Dawg, brainliest please.

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4 years ago
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Grace cut 3 pieces of ribbon; each piece was 2/5 of a foot long.How many feet of ribbon does she have in all?
ser-zykov [4K]

Answer:

6/5 or 1 1/5

Step-by-step explanation:

Each piece is 2/5 so you add it up 3 times or multiply by 3 to get 6/5 or 1 and 1/5.

8 0
3 years ago
The value of a computer which was bought for rs40,000 depreciates at 10%annually what will be the cost of computer after 2 years
aalyn [17]

Answer:

Rs32400

Step-by-step explanation:

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Hope it helps :)

3 0
3 years ago
Please help mee pleaseee
nalin [4]

Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

-----------

Since y = \sqrt[5]{x^3} and y = 5, this means we can equate the two expressions and solve for x

y = 5

\sqrt[5]{x^3} = 5

x^3 = 5^5 Raise both sides to the 5th power

x^3 = 3125

x = \sqrt[3]{3125} Apply cube root to both sides

x = \sqrt[3]{125*25}

x = \sqrt[3]{125}*\sqrt[3]{25}

x = \sqrt[3]{5^3}*\sqrt[3]{25}

x = 5*\sqrt[3]{25}

x \approx 14.62009

4 0
3 years ago
Read 2 more answers
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