2 years ago

(WILL MARK BRAINLIST)

Mathematics

1 answer:

mezya [45]2 years ago

4 0

I believe the answer is the second one

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At the first track meet, Lonnie threw the shot put 51 1/3 feet. At the second track meet he threw the shot put 54 1/2 feet. Writ

mars1129 [50]

Answer:

Step-by-step explanation:

At the first track meet, distance of the shot put throw $D_{1}$ = $54\frac{1}{3}$

At the second track meet distance of the throw $D_{2}=54\frac{1}{2}$ feet

Expression that represents the improvement in the throw will be

D = $D_{2}-D_{1}$

D = $54\frac{1}{2}-51\frac{1}{3}$

D = $\frac{109}{2}-\frac{154}{3}$

D = $\frac{327-308}{6}$

D = $\frac{19}{6}$

D = $3\frac{1}{6}$ feet

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Answer:

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Step-by-step explanation:

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timofeeve [1]

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antiseptic1488 [7]

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Step-by-step explanation:

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