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Aloiza [94]
3 years ago
10

Name an angle adjacent to FGI JGI HGJ DGE HGE

Mathematics
2 answers:
bulgar [2K]3 years ago
8 0

The angles adjacent to FGI are FGD and JGI. So, out of given options, JGI is corect.

vichka [17]3 years ago
6 0

Angle FGD is adjacent to angle FGI..

Another example of adjacent angles is in attachment!

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Whats the exponential form of the square root of 9y?
bazaltina [42]

Answer:

3y^{1/2}

Step-by-step explanation:

\sqrt{9y}      

= (9y)^{1/2}  

If you need to simplify:

= (9y)^{1/2}

= 9^{1/2} y^{1/2}

= 3y^{1/2}

5 0
3 years ago
Please Help ! Will Reward Brainliest , Thank You In Advanced.
chubhunter [2.5K]
The answer is y ≤ 8
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4 0
3 years ago
How do you put nine thousand, nine hundred thirty nine in a number
mojhsa [17]

Answer: The numerical form of that number is 9,939.

5 0
3 years ago
Read 2 more answers
A survey organization has used the methods of our class to construct an approximate 95% confidence interval for the mean annual
lawyer [7]

Answer:

\bar X = \frac{66000+70000}{2}= 68000

We can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000

And the margin of error is given by:

ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

And we can rewrite the margin of error like this:

ME =z_{\alpha/2}*SE

Where SE= \frac{\sigma}{\sqrt{n}}

For 95% of confidence the critical value is z_{\alpha/2}= \pm 1.96

The Standard error would be:

SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408

For 99% of confidence the critical value is z_{\alpha/2}= \pm 2.58

And the new margin of error would be:

ME = 2.58* 1020.408 = 2632.653

And then the interval would be given by:

Lower = 68000- 2632.653 = 65367.347

Upper = 68000+ 2632.653 = 70632.653

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The 95% confidence interval is given by (66000 , 70000)

We can estimate the mean with this formula:

\bar X = \frac{66000+70000}{2}= 68000

We can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000

And the margin of error is given by:

ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

And we can rewrite the margin of error like this:

ME =z_{\alpha/2}*SE

Where SE= \frac{\sigma}{\sqrt{n}}

For 95% of confidence the critical value is z_{\alpha/2}= \pm 1.96

The Standard error would be:

SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408

For 99% of confidence the critical value is z_{\alpha/2}= \pm 2.58

And the new margin of error would be:

ME = 2.58* 1020.408 = 2632.653

And then the interval would be given by:

Lower = 68000- 2632.653 = 65367.347

Upper = 68000+ 2632.653 = 70632.653

7 0
4 years ago
A circle has a diameter with endpoints (-7, 1) and (-3, 7).
frozen [14]

Answer: (C) r² = (x+5)²+(y-4)²

Solution:-

The given endpoints are (-7,1) and (-3,7)

so the center will be at the mid point of the line connecting these two points.

hence, center ={ (-7+-3)/2, (1+7)/2 }

hence, C= (-5,4)

so, the equation of the circle is:-

⇒ (x-(-5))²+(y-4)²=r²

or, (x+5)²+(y-4)²=r²

5 0
2 years ago
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