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IgorC [24]
4 years ago
12

Let f(x) = x + 8 and g(x) = x2 − 6x − 7. Find f(g(2)).

Mathematics
2 answers:
blondinia [14]4 years ago
8 0
F(x) = x + 8
g(x) = x² - 6x - 7

f(g(2)) = ((2)² - 6(2) - 7) + 8
f(g(2)) = (4 - 12 - 7) + 8
f(g(2)) = (-8 - 7) + 8
f(g(2)) = -15 + 8
f(g(2)) = -7
just olya [345]4 years ago
3 0
Mathematical Work:
f(x)=x+8
g(x)=x2-6x-7
f(g(2))=(2^2-6(2)-7)+8
f(g(2))=(4-12-7)+8
f(g(2))=-7
Explanation:
f(x)=x+8
g(x)=x2-6x-7
f(g(2))=?
2 was given as the x for function g and when you substitute 2 into function g's equation(g(2)=(2^2-6(2)-7)=-15, you would get -15. The answer to function g would be the x for function f. Which would be f(-15)=-15+8 and the answer for f(g(2)) is -7.
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The volume of the cube is 27x³ + 8y³ +54x²y + 36xy².

<h2>Volume of cube </h2>

The volume of a cube is the cube of its side.

\rm{ Volume\ of\ cube = (side)^3

<h2>Given to us</h2>
  • side length, s = (3x+2y)
  • Volume, V = s³

<h3>Algebraic Identity</h3>

(a+b)^3= a^3 +b^3 +3a^2b+3ab^2

<h3>The volume of the cube</h3>

\begin{aligned}Volume &= s^3\\&= (3x+2y)^3\end{aligned}

Applying algebraic Identity,

            =(3x+2y)^3\\\\ =(3x)^3+(2y)^3+[3\times (3y)^2 \times2y]+[3 \times 3x \times(2y)^2]\\\\= 27x^3 + 8y^3 +54x^2y +36xy^2          

Hence, the volume of the cube is 27x³ + 8y³ +54x²y + 36xy².

Learn more about Algebraic Identity:

brainly.com/question/662239

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