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Alexandra [31]
3 years ago
6

AHHHHHHHHHHHHHHH SOMEONE ANSWEER THIS PLEEASEEE NEED ANSWER ASP 20 pts!! Please answer!!! I literally don't get this ;c so PLEAS

E help
Let P(A)=4/7 and P(B|A)=3/8 .


What is the probability of events A and B occurring?


Enter your answer as a fraction in simplest form.
Mathematics
2 answers:
Blababa [14]3 years ago
6 0

Answer:

P(A\textrm{ and }B)=\frac{3}{14}

Step-by-step explanation:

Given:

P(A)=\frac{4}{7}

P(B|A)=\frac{3}{8}

We know that, conditional probability of B given that A has occurred is given as:

P(B|A)=\frac{P(A\cap B}{P(A)}. Expressing this in terms of P(A\cap B), we get

P(A\cap B)=P(B|A)\times P(A)

Plug in the known values and solve for P(A\cap B). This gives,

P(A\cap B)=P(B|A)\times P(A)\\P(A\cap B)=\frac{3}{8}\times \frac{4}{7}\\P(A\cap B)=\frac{12}{56}=\frac{3}{14}

Therefore, the probability of events A and B occurring is \frac{3}{14}.

viva [34]3 years ago
5 0

Answer:

Step-by-step explanation:

Given:

We know that, conditional probability of B given that A has occurred is given as:

. Expressing this in terms of , we get

Plug in the known values and solve for . This gives,

Therefore, the probability of events A and B occurring is .

Step-by-step explanation:

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