Answer:
B
Step-by-step explanation:
If you take a lokk at the picture I used an online algebra calculator to check my answer against to gurantee the corectness of my answer for you.
We need to find the base x in the following equation:
First, lets convert 365 from base 7 to base 10. This is given by
where the upperindex denotes the position of eah number. This gives
that is, 365 based 7 is equal to 194 bases 10.
Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:
where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives
Now, we have all number in base 10. Then, our first equation can be written in base 10 as
For simplicity, we can omit the 10 and get
so, we can solve this equation for x. By combining similar terms. we have
and by moving 197 to the right hand side, we obtain
Finally, we get
Therefore, the solution is x=5
Answer:
Divide each term by
5
and simplify.
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x
=
2
y
5
+
12
5
4
x
=
28
−
3
y
Replace all occurrences of
x
in
4
x
=
28
−
3
y
with
2
y
5
+
12
5
.
x
=
2
y
5
+
12
5
4
(
2
y
5
+
12
5
)
=
28
−
3
y
Simplify
4
(
2
y
5
+
12
5
)
.
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x
=
2
y
5
+
12
5
8
y
5
+
48
5
=
28
−
3
y
Move all terms in
8
y
5
+
48
5
=
28
−
3
y
to the left side and simplify.
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x
=
2
y
5
+
12
5
23
(
y
−
4
)
5
=
0
Solve for
y
in the second equation.
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x
=
2
y
5
+
12
5
y
=
4
Replace all occurrences of
y
in
x
=
2
y
5
+
12
5
with
4
.
x
=
2
(
4
)
5
+
12
5
y
=
4
Simplify
2
(
4
)
5
+
12
5
.
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x
=
4
y
=
4
The solution to the system of equations can be represented as a point.
(
4
,
4
)
The result can be shown in multiple forms.
Point Form:
(
4
,
4
)
Equation Form:
x
=
4
,
y
=
4
Step-by-step explanation:
The perimeter is the sum of all lengths of the side of a polygon. For a triangle it is expressed as:
P = a + b + c
We let a = 7.3, b = 2.94 and c=x
Therefore, the perimeter of the given triangle is:
14.8 = 7.3 + 2.94 + x
From the options given, the correct answer is the last option. The expression, <span>x - 14.8 = 2.94 + 7.3, will give an erroneous value of the third side. It will be more than the perimeter given.</span>
