Answer:
The correct option is;
ΔCED ~ ΔCAB
Step-by-step explanation:
Given that the translation maps angle ∠D to angle ∠B, we have;
Angle ∠D is congruent to ∠B (Given)
Segment ED is parallel to segment AB (lines having similar angles to a common transversal)
Therefore, ∠A is congruent to ∠E, (Angle on the same side of a transversal to two parallel lines)
∠C is congruent to ∠C reflexive property
Therefore, we have;
∠C ≅ ∠C
∠E ≅ ∠A
∠D ≅ ∠B
Which gives ΔCED is similar to ΔCAB (not ΔCBA)
Answer:
42.1
Explanation step-by-step:
Working out the lenght of the blue-dashed line:
SOH
47 is the Hypotenuse.
the blue line is the adjacent.
adjacent= Cos(30) x47
adjacent= 40.7
Working out x :
40.7 is the opposite this time.
x is the adjacent.
x = 40.7/ Tan(44)
x = 42.1
Suspecting that his parents are going to give him $1,300 continually you would solve like this
$120,000-$100= $19,900
$19,900/$1,300= 92.23
92.23 is the amount of $1,300 donations it would take from his parents, so if he was getting $1,300 month it would take 92.23 months
<span>3(2t + 5) = 5t + 25
6t + 15 = 5t + 25
6t - 5t = 25 - 15
t = 10</span>
Step-by-step explanation:
do u have like a photo or sum to explain it better
