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insens350 [35]
3 years ago
10

Give a real world example of a sample that was used to make a prediction about a population

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
8 0

Understand that statistics can be used to gain information about a population by examining a sample of the population; generalizations about a population from a sample are valid only if the sample is representative of that population.

olchik [2.2K]3 years ago
3 0

Answer:

Understand that statistics can be used to gain information about a population by examining a sample of the population; generalizations about a population from a sample are valid only if the sample is representative of that population. Understand that random sampling tends to produce representative samples and support valid inferences.

Step-by-step explanation:

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What is the x-intercept of the line 5x-2y=10 ?
In-s [12.5K]
I’m pretty sure c is the right answer
4 0
3 years ago
Sam charges $3 per week to care for house plants while the owners are out of town. He had six customers in one two-week period.
fomenos
He spent 28.8 dollars 
Equation- 3*6*2 then divided by 5 times 4 is your answer
4 0
3 years ago
S
Rudiy27

Answer:

<h2>(3, -2)</h2>

Step-by-step explanation:

Put the coordinates of the points to the inequality and check:

y < -1/2x + 2

for (2, 3) → x = 2, y = 3

3 < -1/2(2) + 2

3 < -1 + 2

3 < 1     FALSE

============================

for (2, 1) → x = 2, y = 1

1 < -1/2(2) + 2

1 < -1 + 2

1 < 1    FALSE

============================

for (3, -2) → x = 3, y = -2

-2 < -1/2(3) + 2

-2 < -1.5 + 2

-2 < 0.5      TRUE

============================

for (-1, 3) → x = -1, y = 3

3 < -1/2(-1) + 2

3 < 1/2 + 2

3 < 2 1/2      FALSE

6 0
3 years ago
These box plots show the prices for two different brands of shoes.
nignag [31]

Answer: Choice C

The interquartile range (IQR) for brand A, $10, is less than the IQR for brand B, $20.

===========================================================

Explanation:

Let's go through the answer choices one by one to see which is true and which is false. Also, we'll see which is helpful when it comes to the spread.

----------------------

Choice A

The IQR is found by subtracting the values of Q1 and Q3, which are the left and right edges of the box in that order.

For boxplot A, we have an IQR = Q3-Q1 = 80-70 = 10.

So we can immediately rule out choice A because the IQR for boxplot A is not 20, but instead it's 10.

----------------------

Choice B

The statement made in choice B is true, since the center vertical lines represent the median, but it's not useful to determine the spread. The median only tells us the center of the distribution. It doesn't tell us how spread out the distribution is.

Imagine you didn't have access to the graph. Now if you're told that the median for brand A is larger than brand B's median, then you'd probably think boxplot A is more spread out; however, the boxplot diagram shows the opposite is the case.

So again the median isn't used here. We can rule out choice B.

----------------------

Choice C

This statement is true. We subtract the box edge values to get the IQR values for each boxplot

For brand A we have IQR = Q3-Q1 = 80-70 = 10

For brand B we have IQR = Q3-Q1 = 70-50 = 20

This is the answer we're after.

The IQR is one tool we can use to measure the spread. The range is another option. We could also use the variance or the standard deviation (two slightly similar ideas) to measure the spread.

As you can see from the diagram, the larger the IQR, the more spread out the data will be.

----------------------

Choice D

This is false because earlier we've shown 10 is the IQR for brand A.

7 0
3 years ago
Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un
Snowcat [4.5K]

Answer:

2nd car is running faster than the first car by 2.01 units.

Step-by-step explanation:

Let's assume that

  • the velocity of first car,

v_1\ =\ 20i\ +\ 25j

  • and the velocity of second car

v_2\ =\ 30i

=> speed of first car,

u_1\ =\ \sqrt{(20)^2+(25)^2}

      =\ \sqrt{400+625}

       =\ \sqrt{1025}

       = 32.01 units

and speed of second car,

u_2\ =\ \sqrt{(30)^2+(0)^2}

        = 30 units

u_2\ -\ u_1\ =\ 32.01\ -30

               = 2.01 units

Hence, 2nd car is running faster than the first car by 2.01 units.

8 0
3 years ago
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