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USPshnik [31]
1 year ago
15

In an experiment involving single-cell RNA sequencing (scRNA-seq), researchers looked at the expression levels of a particular g

ene measured by the amount of mRNA from that gene present in tissue samples from mice with diabetes and mice without diabetes. The data for 14 cells in each category are here: Mice with diabetes: 0.099.0.093.0.106, 0.106, 0.102, 0.107.0.103, 0.153, 0.144, 0.153, 0.155.0.152.0.152, 0.155 Mice without diabetes: 0.127,0.120, 0.118, 0.125, 0.123, 0.130.0.115,0.178, 0.175, 0.171, 0.173.0.172, 0.164, 0.170 Use R to make two normal QQ plots, one for each sample. Is it plausible the two population distributions are normal?
Mathematics
1 answer:
sineoko [7]1 year ago
8 0

The population difference within the pair is normal.

The population distribution of mice with and without diabetes are identical.

mRNA population distribution for mice with diabetes is shifted relative to the population distribution for mice without diabetes.

Conclusion,

the two population has same shape , the two samples are independent  simple random samples  and the two samples are paired , the population means are the same .

Hence, each of the two population distribution is normal.

To learn more about population difference

brainly.com/question/14257759?

#SPJ4

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A triangle has vertices at A(-2,3), B(2,-2), and C(-2,-2). What is the area of the triangle?
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Answer:

The area of the given triangle ABC is 10 units.

Step-by-step explanation:

we have the area of the triangle when points are given is given by the relation

Area of triangle=

\frac{1}{2} {x1 \times (y2 - y3) + x2 \times (y3 - y1) + x3 \times (y1 - y2)}

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triangle = 1/2*( -2*(-2+2)+2*(-2-3)+(-2)*(3+2))

= 1/2*(0+2*(-5)+(-2)*5)

= 1/2*(-10-10)

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A certain club has 10 members, including Harry. One of the 10 members is to be chosen at random to be the president, one of the
devlian [24]

Answer:

The probability that Harry will be chosen as either as Secretary or as treasurer but not as president out of those 10 members will be \frac{1}{5}.

Step-by-step explanation:

We have 10 members out of which one is Harry, we need to choose one of the 10 members as President, one to be as secretary out of the remaining 9, one  as the treasurer of the remaining 8 members.

We want harry to be as either as secretary or as treasurer. so we will consider both the cases

Probability is given by = No of favorable outcomes/ Total no of outcomes

(1) Harry as secretary : If harry is to be chosen as secretary then he can't be a president or he cant be a Treasurer

  As president = \frac{1}{10}

  Not as president = 1 - \frac{1}{10} = \frac{9}{10}

Now he is selected for the secretary so he can't be selected as treasurer.

Not as treasurer = 1

Probability for chosen as secretary = \frac{9}{10}*\frac{1}{9}*1  = \frac{1}{10}  

(2) Harry as treasurer : If harry is to be chosen as the treasurer so he can't be chosen as a President or as a Secretary.

Probability for not chosen as president = \frac{9}{10}

Probability for not chosen as secretary =  1-\frac{1}{9} = \frac{8}{9}

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Probability to be chosen as Treasurer = \frac{9}{10}*\frac{8}{9}*\frac{1}{8} = \frac{1}{10}

Total probability for Harry to be chosen as either secretary or as treasurer will be = P(Secretary) +P(Treasurer)

           = \frac{1}{10} +\frac{1}{10}  = \frac{1}{5}

Therefore the probability that Harry will be chosen as either as Secretary or as treasurer but not as president out of those 10 members will be \frac{1}{5}.

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