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3 years ago

Determine the value of angle x and angle y

Mathematics

1 answer:

ss7ja [257]3 years ago

5 0

Answer:

Step-by-step explanation:

Sum of interior angles of a polygon = (n-1)x180= (6-2)x180=720

Since this looks like a regular hexagon each interior angle =720/6=120

Hence the inside angle touching the line is 120 (inside the hexagon)

Since one side of the hexagon is parallel to the line, y and 20 form adjacent angle, sum 180,

Then y= 180-20=160

Then x=360-(160+120)=80 because sum of all angles round a point=360

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3 years ago

Find the Area of the figure below, composed of a parallelogram and two semicircles. Round to the nearest tenths place.

svet-max [94.6K]

Answer:

100.3 units²

Step-by-step explanation:

✅Find the area of the parallelogram:

Area of Parallelogram is given as base × height

base = 10

height = 5

Area of Parallelogram = 10*5 = 50

✅Next, find the area of the two semicircles:

The two semicircles = 1 circle

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3 years ago

What is the product? (x2+3y+7) [yy+1)

DIA [1.3K]

2 x y2 + 2 x 3 y3 + 3y + 7 y2 + 7

6 0

3 years ago

Help please, I’m not sure

JulijaS [17]

$\frac{ \frac{7}{24} }{ \frac{35}{48} } = \frac{2}{5}$

4 0

3 years ago

Find dx/dt when y=2 and dy/dt=1, given that x^4=8y^5-240 dx/dt=

katrin2010 [14]

Answer:

The value of $\frac{dx}{dt}$ is $\frac{160}{x^3}$ .

Step-by-step explanation:

The given equation is

$x^4=8y^5-240$

We need to find the value of $\frac{dx}{dt}$ .

Differentiate with respect to t.

$4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0$ $[\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]$

$4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}$

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

$4x^3\frac{dx}{dt}=40(2)^4(1)$

$4x^3\frac{dx}{dt}=40(16)(1)$

$4x^3\frac{dx}{dt}=640$

Divide both sides by 4x³.

$\frac{dx}{dt}=\frac{640}{4x^3}$

$\frac{dx}{dt}=\frac{160}{x^3}$

Therefore the value of $\frac{dx}{dt}$ is $\frac{160}{x^3}$ .

4 0

3 years ago