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2 years ago

Find the final output of this proposition (((P ∨ Q) → (R ∧ S)) ↔ ¬(¬T ↔ Q)).

Mathematics

1 answer:

jeka942 years ago

8 0

Is this a real question I feel like those emojis are throwing me off

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The amount of soda a dispensing machine pours into a 12 ounce can of soda follows a normal distribution with a mean of 12.48 oun

vampirchik [111]

Answer:

omg 12.80+12.48=.....

Step-by-step explanation:

I told u anwser St top hahahahaha

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2 years ago

Drag each equation to show if it could be a correct first step to solving the equation 3(6+x)=24.

34kurt

Answer:

x=2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

4 0

2 years ago

Pls answer this questionn plss ill mark u brainliest

DedPeter [7]

Okay so there are 100 white balloons, 200 pink balloons, and we are specified that the ratio of pink to yellow is 10:1 soo we can plug 200:20 which can be simplified to 100:10 which can then be simplified to 10:1 there is our ratio. So there are 29 yellow balloons. Therefore there are only 80 balloons left which would mean there are 80 blue balloons!:)

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2 years ago

Simplify

jeka57 [31]

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill\\\\ x^5\div y^2\times x^3\times y^5\implies \cfrac{x^5}{y^2}\cdot x^3\cdot y^5\implies x^5\cdot y^{-2}\cdot x^3\cdot y^5 \\\\\\ x^{5+3}y^{-2+5}\implies x^8y^3$

4 0

3 years ago

Read 2 more answers