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Nataly [62]
3 years ago
13

How do you dilate a figure on a coordinate plane if you want to make the shape larger? How would your steps change if you want t

o make the image smaller?
Mathematics
1 answer:
Papessa [141]3 years ago
3 0
If u want to make the shape larger, u will have to multiply it by the scale factor that is greater then 1.

if u want to make the shape smaller, then u will multiply by the scale factor that is between 0 and 1

if the scale factor is 1, then the shapes are congruent
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Answer:

3 weeks: 21.5 inches

w weeks: 20+0.5w inches

Step-by-step explanation:

Equation: 20+0.5w.

20 was when it was first planted and 0.5 is the amount it grows per week.

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Find the unit vector in the direction of u = (-3,2).
DENIUS [597]
\bf \textit{unit vector for }(a,b)\implies \left( \cfrac{a}{\sqrt{a^2+b^2}}~~,~~\cfrac{b}{\sqrt{a^2+b^2}} \right)\\\\
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(-3,2)\qquad \stackrel{unit~vector}{\implies }\qquad \left( \cfrac{-3}{\sqrt{(-3)^2+2^2}}~~,~~\cfrac{2}{\sqrt{(-3)^2+2^2}} \right)
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\left( -\cfrac{3}{\sqrt{13}}~~,~~ \cfrac{2}{\sqrt{13}}\right)\\\\
-------------------------------

\bf \textit{and now let's \underline{rationalize} the denominator for each}
\\\\\\
-\cfrac{3}{\sqrt{13}}\cdot \cfrac{\sqrt{13}}{\sqrt{13}}\implies -\cfrac{3\sqrt{13}}{13} \qquad \qquad \qquad \qquad  \cfrac{2}{\sqrt{13}}\cdot \cfrac{\sqrt{13}}{\sqrt{13}}\implies \cfrac{2\sqrt{13}}{13}
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\textit{and written in \underline{ai+bj form}}\qquad -\cfrac{3\sqrt{13}}{13}i~~~~+~~~~\cfrac{2\sqrt{13}}{13}j
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3 years ago
The quotient of a number and 2 is -3 ?
Vera_Pavlovna [14]
The answer to this is x/2 = 3.
4 0
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What is another way to write 56
SashulF [63]

Answer:

\frac{112}{2}

Step-by-step explanation:

Another way to express 56 is \frac{112}{2} because they are equal values.

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1 or 3 sorry if wrong

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