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Klio2033 [76]
3 years ago
8

What is the slope of the line determined by the equation -1/2x+3/4y=0

Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer:

The slope is 2/3

Step-by-step explanation:

-1/2x+3/4y=0

To find the slope, we need to get the equation in the form y= mx+b

Add 1/2x to each side

-1/2x+ 1/2 x+3/4y=0+1/2x

3/4 y = 1/2x

Multiply  by 4/3 to isolate y

4/3 * 3/4 y = 4/3 * 1/2 x

y = 2/3 x

The slope is 2/3 and the y intercept is 0

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If 8 apples cost $5.84, what will be the cost of 18 apples (assuming an equal rate)? use a proportion to solve this problem and
enyata [817]

8 apples ------- $ 5.84

18 apples ------- x


x= (18*5.54)/8 = 12.47

Answer is $ 12.47.

3 0
3 years ago
Alex's dog weighs 7 times as much as her cat. Together, the two pets weigh 72 pounds. How much does Alex's dog weigh?
raketka [301]
D=dog's weight
c=cat's weight
d=7c
d+c=72
sub 7c for d
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7 0
3 years ago
1-116 1.2.6
ankoles [38]

Answer:

A. 30 adults; B. 24 not dolls

Step-by-step explanation:

A.

\begin{array}{rcl}\text{No. of adults} & = & \text{No. of visitors} \times \text{Fraction who are adults}\\& = & \text{100 visitors} \times \dfrac{\text{3 adults}}{\text{10 visitors}} \\& = & \textbf{30 adults}\\\end{array}

B.

If five-eighths of the prizes were dolls, then three-eighths of the prizes were not dolls.

\begin{array}{rcl}\text{No. not dolls} & = & \text{No. of prizes} \times \text{Fraction not dolls}\\& = & \text{64 prizes} \times \dfrac{\text{3 not dolls}}{\text{8 prizes}} \\& = & \textbf{24 not dolls}\\\end{array}

3 0
3 years ago
Which of the following is the simplest form of this expression?
Readme [11.4K]
The numerator could be written a⁴/⁵

The denominator could be written a²/³


Now solve  ( a⁴/⁵) / (a²/³) ==> a⁽⁴/⁵ ⁻²/³)  = a⁽²/¹⁵)

This is the simplest way
4 0
3 years ago
Read 2 more answers
1 point) Use Stoke's Theorem to evaluate ∫CF⋅dr∫CF⋅dr where F(x,y,z)=xi+yj+1(x2+y2)kF(x,y,z)=xi+yj+1(x2+y2)k and CC is the bound
Drupady [299]

Answer:

0

Step-by-step explanation:

Thinking process:

\int\limits^a_b {cF} \, .dr

= \int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx curlFdS by Stoke's Theorem

= \int\limits^a_b {} \,  \int\limits^a_b {} \, < 12y, -12x, 0 > .< z_x,-z_y, 1 > dA\\= \int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< 2x, 2y, 1 > dA since z = 25-x^{2} -y^{2} \\= 0

3 0
3 years ago
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