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liq [111]
2 years ago
15

Help me. pls ...............​

Mathematics
1 answer:
zaharov [31]2 years ago
7 0

Answer:

y-6=-7(x-3)

Step-by-step explanation:

m=y2-y1/x2-x1

m=-8-6/5-3

m=-14/2

m=-7

y-y1=m(x-x1)  point slope

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Find the value of x. Round to the<br> nearest tenth.<br> 40<br> X<br> 7<br> x = [?]
serious [3.7K]
The correct answer for that question is 280
3 0
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8 copies of the sum of 4 thirds and 2 more? (Show your work)
KengaRu [80]

Answer:

40

Step-by-step explanation:

8copies of sum 4/3 and 2

So let's solve

Sum of 4/3and 2

4/3+2

Lcm is 3

4+6/2

10/2

5

8copies means 8 multiply by the sum of 4/3 and 2

So 8(5)

=40

So the answer is 40

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3 years ago
The quarterback for the Dallas Cowboys throws a pass and gains 11 yards on the first down but then
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B. -1
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6 0
3 years ago
A cylinder has a height that is twice the length of the diameter. The diameter of the cylinder is 10 centimeters. What is the su
siniylev [52]

Answer:

Step-by-step explanation:

Givens

pi = 3.14

d = 10 cm

h = 2*d

Formula

  • The top of the cylinder is a solid circle. So the area of the circle is pi r^2
  • There is both a top and bottom to the circle so the fomula is 2*pi*r^2

  • The surrounding area of the cylinder is the circumference of the circle times the height. The circumference of the circle is 2*pi*r.
  • Then you just multiply by the height.
  • formula = 2*pi * r * h

The combined formula is given below.

SA = 2*pi*r^2  +  2*pi*r * h

Conversions

d = 10 cm

h = 2*10

h = 20 cm

r = d/2

r = 10 / 2

r = 5cm

Solution

SA = 2*pi*r^2  +  2*pi*r * h

SA = 2*3.14*5^2 + 2*3.14*5*20

SA = 157 + 628

SA = 785 cm^2

Answer: The surface area is 785 cm^2

5 0
2 years ago
F(x)=x^3+3
lawyer [7]

Answer:

  (a)   -3/4

  (b)  -0.75

  (c)  -0.75

Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

  • evaluating the function at the midpoint of the bracketing interval
  • choosing a smaller bracketing interval
  • identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

__

(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

__

(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

__

(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

__

See the attached table for function values.

_____

<em>Comment on bisection iteration</em>

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.

5 0
3 years ago
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