If 100.0 grams of na3n decompose to form sodium and nitrogen, how many moles of sodium are formed? write and balance equation be
2 answers:
Answer:
3.62 moles
Explanation:
Sodium nitride (Na₃N) will decompose as shown in the balanced equation below
2Na₃N → 6Na + N₂
The molar mass of sodium nitride in the solution is
Mass of Na above is (2 ₓ 3 ₓ 23) = 138 g
Mass of N above is (2 ₓ 14) = 28 g
Mass of Na₃N = 138g + 28g = 166g
From the equation above, we can deduce that 166g of Na₃N will produce 6 moles of sodium. Hence 100g of Na₃N will produce X moles of sodium where X is unknown.
∴ 166g of Na₃N → 6 moles of Na
100g of Na₃N → X moles of Na
When the above is cross multiplied,
X =
X = 3.62 moles
3.62 moles of sodium (Na) will be formed when 100g of Na₃N decomposes
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Explanation:
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The picture attached shows the structures, they are labeled as 1, 2 and 3, according to this problem.
In the chair structure, according to the picture below, you can see that both methyls are heading in the axial positions of the ring (One facing upward and the other downward). This is pretty stable, however, when the methyls are in those positions, the methyl position 1, can undergoes an 1,3 diaxial interactions with the hydrogens atoms (They are not drawn, but still are there), so this interaction makes this structure a little less stable that it can be.
On the other side, the ring flipped structure, we can see that both methyls are in the equatorials positions of the ring, and in these positions, it can avoid the 1,4 diaxial interactions with the hydrogens atoms, making this structure the most stable structure.
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