Question

If 100.0 grams of na3n decompose to form sodium and nitrogen, how many moles of sodium are formed? write and balance equation before solving

Answer 1

The balanced equation is:
$2Na_3N-\ \textgreater \ 6Na + N_2$

Then proceed with the following equations.


$100g Na_3N*(\frac{1molNa_3N}{82.98gNa_3N})*(\frac {6mol Na}{2molNa_3N})*(\frac {22.99gNa}{1molNa})=83.12gNa$

The answer is $83.12gNa$.

Answer 2

Answer:

3.62 moles

Explanation:

Sodium nitride (Na₃N) will decompose as shown in the balanced equation below

2Na₃N → 6Na + N₂

The molar mass of sodium nitride in the solution is

Mass of Na above is (2 ₓ 3 ₓ 23) = 138 g

Mass of N above is (2 ₓ 14) = 28 g

Mass of Na₃N = 138g + 28g = 166g

From the equation above, we can deduce that 166g of Na₃N will produce 6 moles of sodium. Hence 100g of Na₃N will produce X moles of sodium where X is unknown.

∴ 166g of Na₃N →  6 moles of Na

100g of Na₃N → X moles of Na

When the above is cross multiplied,

X = $\frac{100 * 6}{166}$

X = 3.62 moles

3.62 moles of sodium (Na) will be formed when 100g of Na₃N decomposes