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Nookie1986 [14]
3 years ago
9

The academic computing committee at a college is in the process of evaluating different computer systems. The committee consists

of five ​administrators, seven ​faculty, and four students. A six person subcommittee is to be formed. The chair and vice chair of the committee must be​ administrators; the remainder of the committee will consist of faculty and students. In how many ways can this subcommittee be​ formed?
Mathematics
1 answer:
mr Goodwill [35]3 years ago
5 0
There are 3,300 different ways to select the committee.

First, we need to determine the total number of ways the 6 members can be selected.

For the chair and vice chair, it would be 5 x 4 = 20, but then that has to be divided by 2. (Because the order doesn't matter)
20 / 2 = 10

For the rest, it would be 11 x 10 x 9 x 8 = 7920, but again divide it by 4! because the order doesn't matter.
7920 / 24 = 330

To find the total ways for both, multiply 10 by 330 to get 3300.
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If x varies directly as y, and x = 7.5 when y = 10, find x when y = 4.
Lilit [14]
The answer is A) 3.
I hope this helps.
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The cost of a 12.95 pizza was shared evenly by 5 friends. How much did each person pay?
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3 years ago
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Ahmed learned: "To multiply a whole number by ten, just place a zero at the end of the number." For
Gala2k [10]

Answer:

a) 2x^4 + 8x^3 + x^2 + 3x

b) evaluate this polynomial at x = 10

Step-by-step explanation:

Hi!

a)

The product of a sum is the sum of the products, having said this:

(2x^3 + 8x^2 + x + 3) \times x = 2x^4 + 8x^3 + x^2 + 3x

b)

We can use the result from part a and consider x = 10.

First lets take the first polynomial

2x^3 + 8x^2 + x + 3 = 2(10)^3 + 8 (10)^2+10^1+3(10)^0

Knowing that every number (excepting probably 0, which could be undefined for some or 1 for others) to the power of 0 is one:

2x^3 + 8x^2 + x + 3 = 2(1000)+ 8(100)+10+3(1) = 2813

Which is the initial number

Now lets conisder the product of the polynomial times x and evaluate it at x=10:

(2x^3 + 8x^2 + x + 3) \times x = 2x^4 + 8x^3 + x^2 + 3x

(2(10)^4 + 8(10)^3 + 10^2 + 3(10) = 2 (10000) + 8(1000) + 100 + 3(10)

= 28130

We can now see that teh rule is treu because we can see the whole number as a sum of numbers from 0 to 9 multiplied by a power of 10, and when it is multiplied by 10, each power increases by one, and at the end, the final result is adding a zero at the end

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3 years ago
4n + 25 = 5n + 20 and n=5 plug it in?​
rusak2 [61]
4n+25=5n+20
20+25=25+20
45=45
8 0
3 years ago
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