When plate movement rocks to break its called

Which term describes a test that scientist use to answer a question?

antoniya [11.8K]

The scientific method?

8 0

4 years ago

An electron of kinetic energy 1.59 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 35.4 cm

Blizzard [7]

Answer:

a) $v = 2.36 \cdot 10^{7} m/s$

b) $B = 3.80 \cdot 10^{-4} T$

c) $f = 1.06 \cdot 10^{7} Hz$

d) $T = 9.43 \cdot 10^{-8} s$

Explanation:

a) We can find the electron's speed by knowing the kinetic energy:

$K = \frac{1}{2}mv^{2}$

Where:

K: is the kinetic energy = 1.59 keV

m: is the electron's mass = 9.11x10⁻³¹ kg

v: is the speed =?

$v = \sqrt{\frac{2K}{m}} = \sqrt{\frac{2*1.59 \cdot 10^{3} eV*\frac{1.602 \cdot 10^{-19} J}{1 eV}}{9.11 \cdot 10^{-31} kg}} = 2.36 \cdot 10^{7} m/s$

b) The electron's speed can be found by using Lorentz's equation:

$F = q(v\times B) = qvBsin(\theta)$ (1)

Where:

F: is the magnetic force

q: is the electron's charge = 1.6x10⁻¹⁹ C

θ: is the angle between the speed of the electron and the magnetic field = 90°

The magnetic force is also equal to:

$F = ma_{c} = m\frac{v^{2}}{r}$ (2)

By equating equation (2) with (1) and by solving for B, we have:

$B = \frac{mv}{rq} = \frac{9.11 \cdot 10^{-31} kg*2.36 \cdot 10^{7} m/s}{0.354 m*1.6 \cdot 10^{-19} C} = 3.80 \cdot 10^{-4} T$

c) The circling frequency is:

$f = \frac{1}{T} = \frac{\omega}{2\pi} = \frac{v}{2\pi r}$

Where:

T: is the period = 2π/ω

ω: is the angular speed = v/r

$f = \frac{v}{2\pi r} = \frac{2.36 \cdot 10^{7} m/s}{2\pi*0.354 m} = 1.06 \cdot 10^{7} Hz$

d) The period of the motion is:

$T = \frac{1}{f} = \frac{1}{1.06 \cdot 10^{7} Hz} = 9.43 \cdot 10^{-8} s$

I hope it helps you!

8 0

3 years ago

How does wheel and axel work

Andrew [12]

Once the object is moving, the force of friction opposes the force exerted on the object. The wheel and axle makes this easier by reducing the friction involved in moving an object.

Hope it helps!

4 0

3 years ago

Read 2 more answers

Help needed

MakcuM [25]

Answer: Atmosphere and geosphere.

Geo-sphere is the solid part of the earth. Hydrosphere is the water part. The living things on the earth make up the biosphere. The gases, water vapors etc make up the atmosphere. When a volcanic eruption adds carbon dioxide to the air, the carbon-dioxide is being added from geosphere to the atmosphere. Hence, there is interaction between atmosphere and geosphere.

6 0

4 years ago

A 3 inch fire hose has a water flow of 200 gallons per minute. What is the flow in liters per second? Note: Use US gallons not U

stepladder [879]

Answer:

Case I: 12.617 L/s

Case II: 161.406 cubic meters per hour

Case III: 1.062 Pound inches

Explanation:

<u>Given:</u>

Speed of water flow = 200 gallons per minute
Speed of air blow = 95 cubic feet per minute
Measure of Torque = 12 Newton centimeter

<u>Assumptions:</u>

1 US gallon = 3.785 L
1 min = 60 s
1 ft = 0.3048 m
1 h = 60 min
1 inch = 2.54 cm
1 N = 0.2248 lb

Case I:

$Speed\ of\ water\ flow = 200 \dfrac{gallon}{min}\\\Rightarrow V_{water} = 200\times \dfrac{3.785\ L}{60\ s}\\\Rightarrow V_{water} = 12.617\ L/s$

Case II:

$Speed\ of\ air\ blow = 95 \dfrac{ft^3}{min}\\\Rightarrow V_{air} = 95\times \dfrac{(0.3048\ m)^3}{\dfrac{1}{60}\ h}\\\Rightarrow V_{air} = 95\times (0.3048)^3\times 60\ m^3/h\\\Rightarrow V_{air} = 161.406\ m^3/h$

Case III:

$Measure\ of\ torque = 12\ N cm\\\Rightarrow \tau = 12\times (0.2248\ lb)\times \dfrac{1}{2.54}\ in\\ \Rightarrow \tau = 1.062\ lb in$

6 0

3 years ago