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4 years ago

Help needed

Physics

1 answer:

MakcuM [25]4 years ago

6 0

Answer: Atmosphere and geosphere.

Geo-sphere is the solid part of the earth. Hydrosphere is the water part. The living things on the earth make up the biosphere. The gases, water vapors etc make up the atmosphere. When a volcanic eruption adds carbon dioxide to the air, the carbon-dioxide is being added from geosphere to the atmosphere. Hence, there is interaction between atmosphere and geosphere.

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What is the gravitational force between two 1 kg objects that are 1 m apart?

lapo4ka [179]

Answer:

$F=6.67\times 10^{-11}\ N$

Explanation:

Given that,

The masses of two objects, m₁ = m₂ = 1 kg

The distance between masses, d = 1 m

We need to find the gravitational force between two masses. The force is given by the relation as follows :

$F=G\dfrac{m_1m_2}{d^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1\times 1}{(1)^2}\\F=6.67\times 10^{-11}\ N$

So, the force between two masses of 1 kg is $6.67\times 10^{-11}\ N$ .

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3 years ago

Which renewable resource generates the greatest amount of energy?

gayaneshka [121]

Answer:

Coal

Explanation:

Coal because it has grader than everything thing else. Coal has 33.2 that is grader then everything else.

<em>Hope this helps! </em>

7 0

3 years ago

Read 2 more answers

What type of drawing is shown in the figure?

Rasek [7]

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What type of drawing is shown in the figure?

Answer:

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6 0

3 years ago

How does the kinetic energy of particles vary with temperature

Bezzdna [24]

When the average kinetic energy of the molecules go up ( a rise in temperature) the average speed of the molecules increases, the molecules now on average have more kinetic energy .

6 0

4 years ago

In an RL series circuit, an inductor of 3.54 H and a resistor of 7.76 Ω are connected to a 26.6 V battery. The switch of the cir

podryga [215]

Answer:

Energy stored in inductor will be 20.797 J

Explanation:

We have given inductance L = 3.54 H

And resistance R = 7.76 ohm

Battery voltage V = 26.6 VOLT

After very long time means at steady state inductor behaves as short circuit

So current $i=\frac{V}{R}=\frac{26.6}{7.76}=3.427Amp$

Now energy stored in inductor $E=\frac{1}{2}Li^2=\frac{1}{2}\times 3.54\times 3.427^2=20.797J$

So energy stored in inductor will be 20.797 J

4 0

4 years ago