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2 years ago

8

Jayla made 36 sugar cookies for the class party. Before you got to class the teachers ate 9 cookies, and then your classmates at

e 1/3 of the remaining cookies. How many cookies are left for you to eat?

1 answer:

oksian1 [2.3K]2 years ago

8 0

Answer:

9 cookies are left

Step-by-step explanation:

36 - 9 = 27

27 · 1/3 = 9

You might be interested in

The sum of Rhonda and her daughter Tenica’s age is 64. The difference in their ages is 28. How old is each person?

iragen [17]

Answer:

The mother (Rhoda) is 46 years old.

The daughter (Tenica) is 18 years old

Step-by-step explanation:

Let the age of the mother (Rhoda) be m

Let the age of the daughter (Tenica) be d.

The sum of Rhonda and her daughter Tenica’s age is 64. This can be written as:

m + d = 64 ... (1)

The difference in their ages is 28. This can be written as:

m – d = 28 ... (2)

From the above illustrations, the equation obtained are:

m + d = 64 ... (1)

m – d = 28 ... (2)

Solving by elimination method:

Add equation 1 and 2 together

. m + d = 64

+ m – d = 28

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

2m = 92

Divide both side by 2

m = 92/2

m = 46

Substitute the value of m into any of the equation to obtain the value of d. Here, we shall use equation 1

m + d = 64

m = 46

46 + d = 64

Collect like terms

d = 64 – 46

d = 18

Therefore, the mother (Rhoda) is 46 years old and the daughter (Tenica) is 18 years old.

3 0

3 years ago

Sir John Franklin was an explorer who traveled in Canada and the United States he was 33 years old when he began exploring North

Dmitry_Shevchenko [17]

He was 51 years old. He was 33 when he first started exploring. Then 17 years later he explored again so you add 17 +33 =50 . Then 11 years later he died so you add 11 to 50 =51

7 0

3 years ago

In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th

MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

$\frac{20!}{18!2!}=190$

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0

3 years ago

You are a personnel director and are interested in predicting the Number of Shares of Company Stock (Y) using the Number of Year

hoa [83]

Answer:

intercept=b0=75

Step-by-step explanation:

The least squares estimate of the intercept b0 can be computed as

b0=ybar-b1*xbar.

ybar=average number of shares of company stock=525.

xbar= average number of years employed=22.5.

slope=b1=20.

Thus,

intercept=b0=ybar-b1*xbar

intercept=b0=525-20*22.5

intercept=b0=525-450

intercept=b0=75.

Thus, the estimate of intercept b0=75.

8 0

3 years ago

Ashley, Bob, Claire, and Daniel are among 13 students who entered a lottery to win a free vacation to Paris.

AlladinOne [14]

Answer:

0.0014 = 0.14% probability that Ashley, Bob, Claire, and Daniel will be chosen.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the students are chosen is not important, so the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes:

4 students from a set of 4(Ashley, Bob, Claire, and Daniel). So

$D = C_{4,4} = \frac{4!}{4!(4-4)!} = 1$

Total outcomes:

4 students from a set of 13(number of students in the lottery). So

$T = C_{13,4} = \frac{13!}{4!(13-4)!} = 715$

Probability:

$p = \frac{D}{T} = \frac{1}{715} = 0.0014$

0.0014 = 0.14% probability that Ashley, Bob, Claire, and Daniel will be chosen.

7 0

3 years ago