2 years ago

Solve. 2log(x+1)-log(x+3)=log1

Mathematics

1 answer:

guapka [62]2 years ago

4 0

Answer: x = 1

Step-by-step explanation:

2log(x+1) - log (x+3) = log 1

log(x+1)^2 - log (x+3) = log 1

log [(x+1)^2 / (x+3)] = log 1

(x+1)^2 / (x+3) = 0

(x+1)^2 = 0

x = 1 or x = -1 (rejected, as log0 does not exist)

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