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2 years ago

9

Which is the pathway of light as it travels through the eye?cornea → iris → retina → lenscornea → iris → lens → retinairis → cor

nea → lens → retinaretina → lens → iris → cornea

1 answer:

Vikki [24]2 years ago

7 0

Answer:

Cornea >iris>lens >retina

Explanation:

Can't exactly figure out the answer but I think it should look like this

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A mixture of compounds containing diethylamine, phenol, ammonia, and acetic acid is separated using liquid-liquid extraction as

umka2103 [35]

Answer:

I would expect to extract the acetic acid.

Explanation:

In the first step, since we are adding a concentrated acid,<u> it will react with the bases present in the mixture (diethylamine and ammonia) </u><u>forming salts</u><u>, </u><u>which are soluble in water</u>. Therefore, after draining the aqueous layer, we will have phenol and acetic acid left in the organic layer.

In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.

7 0

3 years ago

Helpppp meee plzzzzzzz

JulijaS [17]

5- sr +2 O -2. SrO
6- Mg +2 F-1 MgF2
7- B+3 P-3 BP
8- Li +1 N-3 Li3N
9- Ba +2 Br -1 BaBr2
10- Al +3 P -3 AlP

6 0

3 years ago

larisa [96]

Answer:

group I: alkali metals

group II (beryllium to radium): alkaline earth metals

group II (scandium to zinc , yttrium to cadmium, lanthanoid series to mercury, actinoid series to copernicium): transition metals

group VII (fluorine to astatine): halogens

group VIII: (helium to radon): noble gases

Explanation:

3 0

3 years ago

You perform a single extraction with 100 mL of chloroform to remove compound A from 100 mL of an aqueous solution. The partition

Mice21 [21]

Answer:

Percentage of mass of solute in aqueous phase is 28.57%.

Explanation:

$(q)_{aq}$ - Fraction of solute in aqueous phase.

$(q)_{aq}=\frac{V_{aqueous}}{DV_{organic}+V_{aqueous})}$

$V_{aqueous}$ = Used volume of aqueous solution

$V_{organic}$ = Used volume of organic solution

D = partition coefficient.

$(q)_{aq}=\frac{100ml}{(2.5\times100)+100\,ml}=0.2857$

Mass of solute in aqueous phase = $0.2857\times 5g=1.428g$

$Mass\,percentage = \frac{1.428}{5.0}\times 100=28.57$

Therefore, Percentage of mass of solute in aqueous phase is 28.57%.

5 0

3 years ago

WILL GIVE BRAINLIEST

k0ka [10]

I think the answer would b C

6 0

3 years ago