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aev [14]
2 years ago
7

Help me please i really need it

Mathematics
1 answer:
Sauron [17]2 years ago
5 0

Answer:

Multiply each number by the little number next to it then add. It will be a huge number.

Step-by-step explanation: Above.

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X and Y are continuous values, both measured to 2 significant figures. X=230 and Y=400. work out the greatest possible value of
kirill115 [55]
"Two significant figures" means that a digit after the second one could actually be anything ... it wasn't measured. 'X' could be anything from 230 to 239. 'Y' could be anything from 400 to 409. The greatest possible value of that fraction is. (239)/(409 squared) .
8 0
3 years ago
Determine whether the function is odd, even, neither, or can’t be determined: g(x) = x2 + x Question options:
Anastasy [175]

I have already done this question. The correct answer is c

7 0
3 years ago
Read 2 more answers
Solve for x - PLEASE NEED HELP, this is my 3rd time posting it.
mafiozo [28]

Answer:

x=58

Step-by-step explanation:

First, remember that the maximum degree of an angle totals 360°.

Since we already have 294°, this means that what is left must total 360\textdegree - 294\textdegree= 66\textdegree.

Therefore, this means that our two smaller angles must equal 66°. So:

(36)+(x-28)=66

Solve for x. Add on the left:

x+8=66

Subtract 8 from both sides. Therefore, the value of x is:

x=58

6 0
3 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
73.085 in standard form
jeka57 [31]

Eres una pinche pendejha huevona

Hija de tu re Phuta bomba madreh, tienes una cara de vaca y puedes venir a mamrmeh la vergha

7 0
3 years ago
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