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2 years ago

The supermarket has 10 aisles. 1 of the aisles is empty. What percentage of the aisles are empty?

Mathematics

2 answers:

GarryVolchara [31]2 years ago

7 0

Answer:

10%

Step-by-step explanation:

1 out of 10 isles is the same as doing 1 divided by 10, which gets 0.1. To make this a percentage you would multiply it by 100 to get 10%

kodGreya [7K]2 years ago

6 0

10%

Mark brainliest please

Hope this helps you

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Negative solution for Multi-step equations

nydimaria [60]

Answer:

$\frac{1}{2}(4x+6)+3x=7x+9$

$\frac{1}{2}(4x+8)+3x=7x+9$

Step-by-step explanation:

By putting the numbers in the given equation,

$\frac{1}{2}(4x+6)+3x=7x+9$

2x + 3 + 3x = 7x + 9

5x + 3 = 7x + 9

(5x + 3) - 7x = (7x + 9) - 7x

(5x - 7x) + 3 = 9

-2x + 3 = 9

(-2x + 3) - 3 = 9 - 3

-2x = 6

$-\frac{2x}{2}=\frac{6}{2}$

-x = 3

x = -3

Therefore, our equation is correct which has a negative result.

In place of 6 if we use 8, value of x will be negative again.

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3 years ago

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stepan [7]

12.6≤g+17.4 Flip the equation. g+17.4≥12.6 Subtract 17.4 from both sides. g+17.4−17.4≥12.6−17.4 g≥−4.8 Answer: g≥−4.8

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2 years ago

Find the measure of an interior and an exterior angle of a regular 46-gon

alina1380 [7]

Exterior is 360 and interior is 7920!

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2 years ago

What is the compound interest on investing $600 for 3 years at 7% per annum?

Brut [27]

Answer:

After investing for 3 years at 7% interest, your $600 investment will have grown to $735.03

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2 years ago

A) Let X be a random variable that can assume only positive integer values, and assume its probability function is P(X -n) A/3^n

kramer

Answer:

a) The value of A = 2

b) The value of $B = \dfrac{1}{12}$

Step-by-step explanation:

Given that:

X should be the random variable that assumes only positive integer values.

The probability function; $P[X = n] = \dfrac{A}{3^n}$ for some constant A and n ≥ 1.

Then, let $\sum \limits ^{\infty}_{n =1} P[X =n] = 1$

This implies that:

$A \sum \limits ^{\infty}_{n =1} \dfrac{1}{3^n}= 1$

$A \times \dfrac{\dfrac{1}{3}}{1 - \dfrac{1}{3}} = 1$

$A \times \dfrac{\dfrac{1}{3}}{\dfrac{2}{3}} = 1$

$A \times \dfrac{1}{2}=1$

A = 2

Thus, the value of A = 2

Suppose X represents a e constant A (n> 1). Find A.

b) Let X be a continuous random variable that can assume values between 0 and 3

Then, the density function of x is:

$f_x(x) = \left \{ {{B(x^2+1)} \ \ \ 0 \le x \le 3 \ \ \ \atop {0} \ \ \ otherwise} \right.$

where; B is constant.

Then, using the property of the probability density function:

$\int ^3_0 \ B (x^2+1 ) \ dx = 1\\$

Taking the integral, we have:

$B \Big [\dfrac{x^3}{3} +x \Big ]^3_0 = 1$

$B \Big [\dfrac{3^3}{3} +3 \Big ]= 1$

$B \Big [\dfrac{27}{3} +3 \Big ] = 1$

B [ 9 +3 ] = 1

B [ 12 ] = 1

Divide both sides by 12

$B = \dfrac{1}{12}$

5 0

2 years ago