It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).
So, use "arctan x" instead.
Then the problem becomes: "differentiate cos (arctan x)."
You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:
(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
300,563 Hope it helps! ^^
~Ash~
Answer:
98°
142°
83°
97°
Step-by-step explanation:
m(arc)JL = 2 × 49° = 98°
m(arc)MJ = 360° - 120° - 98° = 142°
m<KJM = (120° + 46°)/2 = 83°
m<KLM = (360° - 120° - 46°)/2 = 97°
Answer: you can always use
but 30 cubic units
Step-by-step explanation:
because
