Answer:
Explanation:
We apply Newton's second law at the crate :
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Data:
m=90kg : crate mass
F= 282 N
μk =0.351 :coefficient of kinetic friction
g = 9.8 m/s² : acceleration due to gravity
Crate weight (W)
W= m*g
W= 90kg*9.8 m/s²
W= 882 N
Friction force : Ff
Ff= μk*N Formula (2)
μk: coefficient of kinetic friction
N : Normal force (N)
Problem development
We apply the formula (1)
∑Fy = m*ay , ay=0
N-W = 0
N = W
N = 882 N
We replace the data in the formula (2)
Ff= μk*N = 0.351* 882 N
Ff= 309.58 N
We apply the formula (1) in x direction:
∑Fx = m*ax , ax=0
282 N - 309.58 N = 90*a
a= (282 N - 309.58 N ) / (90)
a= - 0.306 m/s²
Kinematics of the crate
Because the crate moves with uniformly accelerated movement we apply the following formula :
vf²=v₀²+2*a*d Formula (3)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
v₀ = 0.850 m/s
d = 0.75 m
a= - 0.306 m/s²
We replace the data in the formula (3)
vf²=(0.850)²+(2)( - 0.306 )(0.75 )
Distance and displacement are hardly ever equal.
Remember that 'displacement' is the straight-line distance between
the start-point and the end-point, regardless of what path you followed
on the way.
So they're equal ONLY when the trip from start to finish was completely
in a straight line.
Answer:
The bikers speed at the top of other hill is <u>25.82 m/s.</u>
Explanation:
Considering the biker is riding on a frictionless surface.
∴ There is no non-conservative or external force acting on the biker.
Hence we can conserve the energy of biker and bike as a system.
Let,
= 44m
= 10m
Since the biker starts from rest , his initial speed = 0 m/s
Let final speed of the bike at the top of other hill be .
∴ Initial Energy (at the top of 44m hill) =
Final Energy (at the top of 10m hill) = .
Conserving both the energies , we get
=
∴
Substituting the values for g , , , we get
= 25.82 m/s
All Offsprings will be round because it comes out as dominant evrytime and it has 0 ressesives. Hope this helped ;)
From looking at the two force equations, you can see the similarities and how gravitational force can be considered parallel to the force between two charges.
Besides being proportional to the inverse of the square of the separation: both forces extend to infinity,They also both travel at the speed of light.