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pychu [463]
2 years ago
8

You push on a 30 kg box with a force of 120 N. What is the acceleration of the box2​

Physics
1 answer:
kumpel [21]2 years ago
8 0

Answer:

6

Explanation:

120/30=6

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The area of the bar over r = 2 is 0.234. what is the area of the bar over r = 4?
natita [175]
The area of the bar over r=4 is 0.468
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3 years ago
A star has an absolute magnitude of 4 and a surface temperature of 5,000 degrees C. According to the HR diagram, list the type o
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On sources it says it would  just be the super giant star 
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3 years ago
: A honeybucket man is carrying his load. He has a pole 2 m long with a bucket hanging from each end. The buckets have a mass of
nasty-shy [4]

Answer:

Explanation:

Using the principle of moment, assuming the rod is uniform rod of mass 1 kg

the center of mass of the rod will be at 1 m

assuming the system is in equilibrium,

clockwise moment = anticlockwise moment

let the distance of the man shoulder be x from the center of gravity and also is the pivot point

total mass of bucket + mass of honey = 2kg + 3 kg =  5 kg for rear bucket and

2kg + 5 kg = 7 kg for front bucket

( 5kg × ( 1+x)) + ( 1 kg × x) = 7 kg × ( 1 - x)

5 + 5 x + x = 7 - 7x

5 + 6x = 7 - 7x

6x + 7x = 7 - 5

13x = 2

x = 2 / 13 = 0.154 m

the honeybucket man's shoulder is 0.154 m from the center of the pole ( forward ).    

8 0
4 years ago
Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin
Oliga [24]

Answer:

Current, I = 1000 A

Explanation:

It is given that,

Length of the copper wire, l = 7300 m

Resistance of copper line, R = 10 ohms

Magnetic field, B = 0.1 T

\mu_o=4\pi \times 10^{-7}\ T-m/A

Resistivity, \rho=1.72\times 10^{-8}\ \Omega-m

We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :

R=\rho \dfrac{l}{A}

R=\rho \dfrac{l}{\pi r^2}

r=\sqrt{\dfrac{\rho l}{R\pi}}

r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}

r = 0.00199 m

or

r=1.99\times 10^{-3}\ m=2\times 10^{-3}\ m

The magnetic field on a current carrying wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

I=\dfrac{2\pi rB}{\mu_o}

I=\dfrac{2\pi \times 0.1\times 2\times 10^{-3}}{4\pi \times 10^{-7}}

I = 1000 A

So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.

4 0
3 years ago
Identify the energy transformations in the following actions.
Artemon [7]
According to the Law of Conservation of Energy, energy is neither created nor destroyed. It is only transferred through different forms of energy. For the following situations, the conversion of energy is as follows:

*Turning on a space heater = electrical energy⇒heat energy
*Dropping an apple core into the garbage =  potential energy⇒kinetic energy
*Climbing up a rope ladder = kinetic energy⇒potential energy
*Starting a car = chemical energy⇒mechanical energy
<span>*Turning on a flashlight = chemical energy</span>⇒electrical energy
4 0
3 years ago
Read 2 more answers
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