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belka [17]
2 years ago
7

How many 6 are in 2/3 pounds?

Mathematics
1 answer:
I am Lyosha [343]2 years ago
6 0

Answer:

There are four sixths in 2/3. Great Question!

Step-by-step explanation:

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You go to the store to buy icecream. The icecream comes in a cylindrical tub that has a diameter of 5 inches and is 4 inches tal
telo118 [61]

Answer:78.5

Step-by-step explanation:

First you find the volume of a cylinder then you plug in the answers don't forget that to find the radius you do diameter divided by 2

5 0
3 years ago
City R has a temperature of -2 degrees. City S has a temperature of -6 degrees. Write an inequality to compare the temperatures
elena-s [515]

Answer:

  -2 > -6  . . .   or  . . .  R > S

Step-by-step explanation:

If you plot the temperatures of the two cities on a number line, you see that the temperature for City R is plotted to the right of the temperature for City S. This means the temperature of City S is less than that of City R.

If your inequality relates cities:

  S < R   or   R > S

If your inequality relates temperatures:

  -6 < -2   or   -2 > -6

3 0
3 years ago
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GuDViN [60]
A bus holds 40 people and a van holds 10

7 0
2 years ago
What does 150 / (-2) equal?
Nookie1986 [14]

Answer:

-75

Step-by-step explanation:

I just checked on a calculator

6 0
2 years ago
Read 2 more answers
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X &gt; 10) b. P(X &gt; 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
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