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Vlada [557]
3 years ago
13

How many moles of gas are in a 1.0 liter canister if the temperature of the canister is 100 K and the pressure is 100 atmosphere

s? R = 0.0821 L*atm/mol*K (Celsius + 273 = Kelvin)
Chemistry
1 answer:
ladessa [460]3 years ago
4 0

Answer:

n = 12.18 moles

Explanation:

Given that,

The volume of a canister, V = 1 L

The temperature of the canister, T = 100 K

Pressure, P = 100 atm

We need to find the number of moles of gas. Let there are n number of moles. We know that,

PV = nRT

Where

R is gas constant, R = 0.0821 L*atm/mol*K

n=\dfrac{PV}{RT}\\\\n=\dfrac{100\times 1}{0.0821 \times 100}\\\\n=12.18\ moles

Hence, there are 12.18 moles of gas.

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tekilochka [14]

Answer:

1 GAS

Explanation:

8 0
4 years ago
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A 20.0–milliliter sample of 0.200–molar K2CO3 so­lution is added to 30.0 milliliters of 0.400–mo­lar Ba(NO3)2 solution. Barium c
iragen [17]

Answer:

[Ba^2+] = 0.160 M

Explanation:

First, let's calculate the moles of each reactant with the following expression:

n = M * V

moles of K2CO3 = 0.02 x 0.200 = 0.004 moles

moles of Ba(NO3)2 = 0.03 x 0.400 = 0.012 moles

Now, let's write the equation that it's taking place. If it's neccesary, we will balance that.

Ba(NO3)2 + K2CO3 --> BaCO3 + 2KNO3

As you can see, 0.04 moles of  K2CO3 will react with only 0.004 moles of Ba(NO3) because is the limiting reactant. Therefore, you'll have a remanent of

0.012 - 0.004 = 0.008 moles of Ba(NO3)2

These moles are in total volume of 50 mL (30 + 20 = 50)

So finally, the concentration of Ba in solution will be:

[Ba] = 0.008 / 0.050 = 0.160 M

6 0
4 years ago
A sample of an unknown compound has a percent composition of 52.14% carbon, 13.13% hydrogen, and 34.73% oxygen. Which compounds
Artemon [7]
<h3>Answer:</h3>

                The two possible compounds are;

                            1) Dimethyl Ether H₃C--O--CH₃

                           2) Ethanol  H₃C--CH₂--OH

<h3>Solution:</h3>

Step 1: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  =  52.14 ÷ 12.01

                      Moles of C  =  4.341 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  =  13.13 ÷ 1.01

                      Moles of H  =  13.00 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  =  34.73 ÷ 16.0

                      Moles of O  =  2.170 mol

Step 2: Find out mole ratio and simplify it;

                C                                        H                                     O

            4.341                                 13.00                              2.170

     4.341/2.170                      13.00/2.170                    2.170/2.170

               2                                      5.99                                    1

               2                                        6                                       1

Hence,  Empirical Formula  =  C₂H₆O

<h3>Result:</h3>

         As the molecular mass of compound is not given therefore, we can assume and guess the empirical formula to be the molecular formula. Hence, possible compounds are,

                            1) Dimethyl Ether H₃C--O--CH₃

                           2) Ethanol  H₃C--CH₂--OH

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Prokaryote cells are single celled organisms
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A 3.5 M KNO3 solution contains 3.5 miles of KNO3 dissolved in A) 1.0 liter of solution B) 1.0 liter of solvent C) 3.5 liters of
Vladimir [108]
N=3.5 mol
c=3.5 mol/L

n=cv

v=n/c

v=3.5/3.5=1.0 L

A) 1.0 liter of solution
4 0
3 years ago
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