Answer:
67.5 moles of O2
Explanation:
2 C
8
H
18 + 27
O
2 → 16
C
O
2 + 18
H
2
O
According to the balanced chemical equation, in normal air % moles of iso-octane will require 67.5 moles of oxygen to combust completely...
D. Catalysts get used up in the formation of the product.
Catalysts are never used up in a reaction.
Explanation:
they can be sorted into solids, liquids, gases and plasma.
Answer: No
Explanation:
- Law of definite proportions is a case from the Law of conservation of energy (matter) which states that "mass can neither be created nor destroyed, but changed from one form to another."
- Adding coefficients to a chemical equation confirms that there is the same number of atoms on both sides of a reaction; therefore, matter has not been created or destroyed but reorganized to give new substrates.
Example : 2 Mg + O2 → 2 MgO
In the balanced equation above, 2 moles of Mg reacts with 1 mole of O2 to produce 2 moles of MgO.
mass of 2 moles of Mg = 24×2= 48 grams
mass of 1 mole of O2 = 16+16 = 32 grams
total mass of reactants = 48 + 32 = 80 grams
mass of 2 moles of MgO = (24+16) ×2 = 80 grams
total mass of products = 80 grams
It is clear that the number of grams of matter before and after the reaction is the same and equals to 80 grams, so obeys the law of definite proportions..
