Quantitative data is any data you receive with a numerical value. So you can measure how many inches with a ruler or pounds with a scale.
This all you need?
Answer:
no. of moles of PbI₂ = 14 moles
Explanation:
Data Given:
no. of moles of HI = 28 moles
no. of moles of Pbl₂ = ?
Reaction Given
Pb + 2HI -------→ Pbl₂ + H₂
Solution:
To solve this problem we have to look at the reaction
Reaction:
Pb + 2HI -------→ Pbl₂ + H₂
2 mol 1 mol
So if we look at the reaction 2 mole of hydrogen iodide (HI) gives 1 moles of Lead iodide (PbI₂), then how many moles of Lead iodide (PbI₂) will be produced by 28 moles of hydrogen iodide (HI)
For this apply unity formula
2 mole of HI ≅ 1 moles of PbI₂
28 mole of HI ≅ X moles of PbI₂
By Doing cross multiplication
moles of PbI₂ = 28 moles x 1 moles / 2 mole
moles of PbI₂ = 14 mole
28 mole of HI will produce 14 moles of PbI₂
Simple 6L of air times the .21L of O2 = 1.26
The relationship between energy of a single photon and its wavelength can be determined using the formula E=hc/lambda where E is energy, h is Planck's constant, c is the speed of light, and lambda is photons.
Before being able to solve for energy, need to convert nanometers to meters.
407 nm (1 m/1 x 10^9 nm) = 4.07 x 10^-7 m
Then plug in the values we know into the equation.
E h(Planck's constant) c(speed of light)
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / 4.07 x 10^-7 m (lambda)
E=(0.000000000000000000000000000000000663js)(300,000,000m/s)=1.989×10^-25j/ms
E=1.989x10^-25j/ms /{divided by} 4.07x10^-7m = 4.8869779x10^-33 J (the meters cancel out)
E = 4.89 x 10^-33 J
This gives us the energy in Joules of a single photon. Now, we can find the number of photons in 0.897 J
0.897J / 4.89 x 10^-33 J = ((0.897 J) / 4.89) x ((10^(-33)) J) = 1.8343558 x 10^-34
1.83435583 × 10-34m4 kg2 / s4 photons
The answer is <span>B) an explosion
An </span>exothermic reaction is a chemical reaction that is caused by heat and light.
Have a good day! =)
