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Molodets [167]
3 years ago
7

19

Chemistry
1 answer:
N76 [4]3 years ago
4 0

Answer:

no. of moles of PbI₂ = 14 moles

Explanation:

Data Given:

no. of moles of HI = 28 moles

no. of moles of Pbl₂ = ?

Reaction Given

        Pb + 2HI -------→ Pbl₂ + H₂

Solution:

To solve this problem we have to look at the reaction

Reaction:

                  Pb  +  2HI   -------→  Pbl₂  +  H₂

                            2 mol          1 mol

So if we look at the reaction 2 mole of hydrogen iodide (HI) gives 1 moles of Lead iodide (PbI₂), then how many moles of Lead iodide (PbI₂) will be produced by 28 moles of hydrogen iodide (HI)

For this apply unity formula

                      2 mole of HI  ≅  1 moles of PbI₂

                      28 mole of HI  ≅  X moles of PbI₂

By Doing cross multiplication

                      moles of PbI₂ = 28 moles x 1 moles / 2 mole

                      moles of PbI₂ = 14 mole

28 mole of HI will produce 14 moles of PbI₂

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7 0
3 years ago
To what volume should you dilute 60.0 mL of a 4.50 M KI solution so that 30.0 mL of the diluted solution contains 3.25 g of KI?
SpyIntel [72]

Answer:

You should dilute to 414.1 mL

Explanation:

Let's apply the dilution formula to solve this:

M conc . Vol conc = M dil . Vol dil

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Molarity for diluted solution → Unknown

Volume for diluted solution → Answer

Let's determine the molarity for diluted solution with data given.

We convert the mass of KI to moles

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Let's convert the volume from mL to L

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Molarity (mol/L) = 0.0195 mol /0.030L = 0.652 M

We replace the data in the formula

4.50 M . 60 mL = 0.652 M . Volume for diluted solution

(4.50M . 60mL) / 0.652M = Volume for diluted solution

414.1 mL = Volume for diluted solution

7 0
3 years ago
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I hope it's helpful!

3 0
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Explanation:

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