Answer:
a) the minimun of acetic anhydride required for the reaction is 2.175 g (CH3CO)2O
b) V acetic anhydride = 2.010 mL
Explanation:
C6H4OHCOOH + (CH3CO)2O ↔ C9H8O4 + C2H4O2
⇒ mol salicylic acid = 2.94 g C6H4OHCOOH * ( mol C6H4OHCOOH / 138.121 g ) = 0.0213 mol C6H4OHCOOH
⇒ mol acetic anhydride = 0.0213 mol C6H4OHCOOH * ( mol (CH3CO)2O / mol C6H4OHCOOH ) = 0.0213 mol (CHECO)2O
⇒ g acetic anhydride = 0.0213 mol * ( 102.1 g/mol ) = 2.175 g CH3CO)2O
b) V = 2.175 g (CH3CO)2 * ( mL / 1.082 g ) = 2.010 mL (CH3CO)2O
Answer:
H2O
Explanation:
PLS MARK ME TO THE BRAINLIST
Answer : The correct option is, (C) 6
Explanation :
Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.
Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.
Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.
The given unbalanced chemical reaction is,
Half reactions of oxidation and reduction are :
Oxidation : ......(1)
Reduction : .......(2)
In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:
Oxidation : ......(1)
Reduction : .......(2)
The overall balanced chemical reaction will be:
From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.
Hence, the correct option is, (C) 6
Answer:
The molar heat capacity of C₂H₆O = 2.797 J/g·°C
Explanation:
The known parameters are first listed as follows from reading the question
Heat transferred, H = 1328 J
Mass of the heated ethanol, m = 40.4 g
Increase in temperature of the heated gas = ΔT = 13.4 °C
Molar mass of ethanol = 46.07 g/mol
Number of moles of ethanol = 40.4/46.07 = 0.877 moles
The heat required to raise the temperature of 40.4 g of ethanol by 13.4 °C is 1328 J
Therefore we have H = m·c·ΔT
c = specif heat capacity = H ÷ (m·ΔT) = = 2.453 J/g·°C
Therefore the heat required to raise the temperature of one mole of ethanol by one degree C = J/g·°C = 2.797 J/g·°C
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