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2 years ago

2. Identify and explain two factors that can influence your skill-related fitness levels.

Physics

1 answer:

zalisa [80]2 years ago

7 0

Genetics and experience (maybe) because sometimes genetics can give u an advantage in activness

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How would you define an ocean current?

Kryger [21]

Answer:

i would describe an ocean current like a pull of the water

Explanation:

water

4 0

2 years ago

Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =

Sloan [31]

Answer:

The current is $I = 8.9 *10^{-5} \ A$

Explanation:

From the question we are told that

The radius is $r = 3.17 \ mm = 3.17 *10^{-3} \ m$

The current density is $J = c\cdot r^2 = 9.00*10^{6} \ A/m^4 \cdot r^2$

The distance we are considering is $r = 0.5 R = 0.001585$

Generally current density is mathematically represented as

$J = \frac{I}{A }$

Where A is the cross-sectional area represented as

$A = \pi r^2$

=> $J = \frac{I}{\pi r^2 }$

=> $I = J * (\pi r^2 )$

Now the change in current per unit length is mathematically evaluated as

$dI = 2 J * \pi r dr$

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

$I = 2\pi \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr$

$I = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr$

$I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.$

$I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]$

substituting values

$I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]$

$I = 8.9 *10^{-5} \ A$

5 0

4 years ago

Se lanza un cohete en un ángulo de 53° sobre la horizontal con una rapidez inicial de 100 m/s. El cohete se mueve por

likoan [24]

Answer:

Explanation:

v = u + at

v₃ = 100 +30.0(3.00) = 190 m/s

s = vt + ½at²

y₃ = (100sin53)(3.00) + ½(30sin53)(3.00²) = 347.4 m

x₃ = (100cos53)(3.00) + ½(30cos53)(3.00²) = 261.8 m

a) v² = u² + uas

s = (v² - u²) / 2a

ymax = 347.4 + (0² - (190sin53)²) / (2(-9.80)) = 1,522 m

b) t₁ = 3.00 s

t₂ = (190sin53) / 9.80 = 15.5 s

t₃ = √(2(1522) / 9.80) = 17.6 s

t = 3.00 + 15.5 + 17.6 = 36.1 s

c) xmax = 261.8 + (190cos53)( 15.5 + 17.6) = 4,047 m

3 0

3 years ago

Studies of the relationship of the Sun to our galaxy-the Milky Way-have revealed that the Sun is located near the outer edge of

lianna [129]

Mass of the milkyway galaxy :

$M_{mw} = \frac{4\pi ^{2}r^{3}}{GT^{2}}\\\\M_{mw} = \frac{4\pi ^{2}(3x10^{4}x9.46x10^{15})^{3}}{6.67x10^{-11}Nm^{2}/Kg^{2}x(7.13x10^{15})^2}\\\\M_{mw } = 2.7x10^{14} Kg$

The magnitude of the mass of the Milky Way galaxy = $2.7x10^{14} Kg$

<h3>Can galaxies recycle stars?</h3>

Galaxies do not appear to have sufficient matter inside them to keep shaping modern stars at the rates that they do. Presently, astronomers have caught a universe within the act of reusing fabric that it already tossed out, which may clarify the discrepancy. New perceptions give the primary coordinate evidence of gas streaming into distant galaxies that are effectively making infant stars, offering support for the "galactic recycling" theory.

To learn more about galactic recycling, visit;

brainly.com/question/6272572

#SPJ4

6 0

2 years ago

A(n) ________ describes the shape of a planet’s orbital path. astronomical unit

sleet_krkn [62]

It is an ellipse.

Hope this helps!

8 0

3 years ago

Read 2 more answers