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2 years ago

Which direction will the box move?

Physics

1 answer:

Yuki888 [10]2 years ago

3 0

Net force

F1-F2-F3
5-10-20
5-30
-25N

As it's negative the box will move left

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What will one see during an annular eclipse?

KATRIN_1 [288]

Partial eclipse, Annular eclipse, Total Eclipse and Hybrid Eclipse are the four different types of the eclipses. When the Sun and Moon are exactly in line with the Earth, the annular eclipse occurs. The new moon is invisible from the earth and it is silhouetted against the sun, this can only be seen in annular eclipse. Annular word means ring shaped, we can see a dark ring of fire in annular eclipse. It has five different stages that are first contact, second contact, maximum eclipse, third contact and 4th contact.

7 0

3 years ago

A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800

Arada [10]

Explanation:

The given data is as follows.

m = 5000 kg, h = 800 km = $0.8 \times 10^{6} m$

$R_{e} = 6.37 \times 10^{6} m$ , r = R + h = $7.17 \times 10^{6} m$

$M_{e} = 5.98 \times 10^{24}$ kg, G = $6.67 \times 10^{-11} Nm^{2}/kg^{2}$

As we know that,

$\frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}$

v = $\sqrt{\frac{GM_{e}}{r^{2}}}$

And, it is known that formula to calculate angular velocity is as follows.

$\omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}$

v = $\sqrt{\frac{GM_{e}}{r^{3}}}$

= $\sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}$

= $1.0402 \times 10^{-3} rad/s$

Thus, we can conclude that speed of the satellite is $1.0402 \times 10^{-3} rad/s$ .

6 0

3 years ago

An 88.0 kg passenger is inside a 1450.0 kg elevator that rises 30.0 m in exactly 1.0 minutes. How much power is needed for the e

OleMash [197]

Answer:

Explanation:

6 0

3 years ago

Helpppp plz heeeeeeeeeeeelp

diamong [38]

Answer:that

Explanation:

8 0

3 years ago

The device shows the relative humidity at 22 degrees celsius. What's the water vapor density if the maximum water vapor in air a

sweet [91]

Answer:

11.6 g/m³

Explanation:

The complete question is,

The device shows the relative humidity at 22 degrees celsius. What's the water vapor density if the maximum water vapor in air at this temperature is 20 gram/cubic meter? a device showing that at 22 degrees celsius the relative humidity is 58%.

Solution:

saturation of water in air is showed by the relative humidity. As it is 58% and not 100%. Lets scale density that we have, if humidity is 100%.

density is 20 gram/m³ when the humidity is 100%

When humidity is 58%

0.58 x 20 = 11.6 g/m³

Therefore, density is 11.6g/m³

6 0

3 years ago