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2 years ago

Workout the value of 5(x-y)

Mathematics

1 answer:

ANTONII [103]2 years ago

6 0

Answer:

5x-5y

Step-by-step explanation:

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I need help pleaseeeeeee

soldi70 [24.7K]

Answer:

For a triangle to be equiangular all its three interior angles must be equal, that is, each angle should measure 60˚.

Step-by-step explanation:

5 0

3 years ago

Plz help will mark brainliest

Kryger [21]

∆ABC=∆DEF

AB=DE –>String

BC=EF–> Rib

m<C=m<F=90° –>List

AC=DF

So m<A=m<D=35 (It is not clear whether the number is 35 or 36, but the same number)

8 0

2 years ago

measure a and measure b are vertical angles with measure a = x and measure b = 4x - 30. what is measure a?

Zolol [24]

Answer:

∠a = 10°

Step-by-step explanation:

The measure of ∠a = x

The measure of ∠b = 4x-30

It is also mentioned that the measure a and measure b are vertical angles. We need to find the value of a.

For vertically opposite angles,

∠a = ∠b

x = 4x-30

4x-30=x

Taking like terms together,

4x-x= 30

3x = 30

x = 10

So, the meausre of ∠a is equal to 10°.

3 0

3 years ago

Vic is standing on the ground at a point directly south of the base of the CN Tower and can see the top when looking at an angle

Sindrei [870]

The angle of elevation of 61° and 72° with the height of the tower being 553.3 m. gives Vic's distance from Dan as approximately 356 meters.

<h3>How can the distance between Vic and Dan be calculated?</h3>

Location of Vic relative to the tower = South

Vic's sight angle of elevation to the top of the tower = 61°

Dan's location with respect to the tower = West

Dan's angle of elevation in order to see the top of the tower = 72°

Height of the tower = 553.3m

$tan( \theta) = \frac{opposite}{adjacent}$

$tan( 61 ^{ \circ}) = \frac{553.3}{ Vic' s\: distance \: to \: tower}$

$distance = \frac{553.3}{tan ( {61}^{ \circ} )} = 306.7$

Vic's distance from the tower ≈ 306.7 m

Similarly, we have;

$Dan's distance = \frac{553.3}{tan ( {72}^{ \circ} )} = 179.8$

Dan's distance from the tower ≈ 179.8 m

Given that Vic and Dan are at right angles relative to the tower (Vic is on the south of the tower while Dan is at the west), by Pythagorean theorem, the distance between Vic and Dan <em>d </em>is found as follows;