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sergey [27]
3 years ago
15

propose a method to check whether a compound is benzene hexene or hexane? (Benzene: C6H6, hexene: C6H12, hexane: C6H14)​

Chemistry
1 answer:
adelina 88 [10]3 years ago
6 0

Solutions of benzene, hexane and hexene can all be separated based on differences in boiling point.

A fail-proof method of identifying compounds is by the use of properties such as boiling point for liquids. Since Hexane, hexene and benzene are all liquids, the liquids can all be subjected to heating and the boiling points of the solutions are observed.

Recall that the boiling points of pure chemical substances have been documented in literature, the boiling points obtained for each sample can be compared with the boiling points in literature and the different solutions can be correctly identified:

Learn more about boiling points:   brainly.com/question/2153588

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10. Given the reaction below, which is the reduced substance? Mg + Cl2 Mg2+ + 2Cl-
atroni [7]

Answer:

2Cl-

Explanation:

When a substance is reduced, it gains electrons. Because electrons are negatively charged, the substance that is reduced will have a negative charge. 2Cl- is the substance that was reduced because it became negative.

7 0
3 years ago
How many moles are in 1.50 grams of ethanol, CH3CH2OH?
LekaFEV [45]
CH3CH2OH = 46.068 (molar mass)
1.50g(1 mole / 46.0680) =
0.03256 moles
4 0
3 years ago
Read 2 more answers
1. Write the chemical equation when excess chloride ion is added to aqueous solution of cobalt chloride. Note observed color of
Aneli [31]

The element cobalt can form compounds in two different oxidation states, +2 and +3. 


The +2 state is more common.

The ion Co2+ (aq) is pink.

Other compounds of cobalt(II), which include both anhydrous Co2+ and complex ions, are commonly blue.

If an aqueous solution contains both cobalt(II) and chloride ions, the blue ion CoCl42- forms, in equilibrium with the pink Co2+ (aq) ion.

<span>CoCl42- (aq) <===========> Co2+ (aq) + 4Cl1-(aq)</span>

5 0
3 years ago
Could anyone help me with question 3?
Anna [14]
Tell me and I can help you with it
8 0
3 years ago
Suppose that you have a 60.0% solution of NaOH. How many milliliters of water must be added to 30.0 mL of this solution to prepa
defon

Answer:

  • <u>21.4 ml (second choice)</u>

Explanation:

<u>1) Data:</u>

a) C₁ = 60.0% (initial solution)

b) V₁ = 30.0 ml (initial solution)

c) C₂ = 0% (pure water)

d) V₂ = ? (pure water)

e) C₃ = 35.0% (final concentration)

<u>2) Formula:</u>

  • C₁V₁ + C₂V₂ = C₃V₃
  • V₁ + V₂ = V₃ (assuming volume addtivity)

<u>3) Solution:</u>

<u />

a) Substitute values in the first formula:

  • 60.0% × 30 ml + 0 = 35% (30 ml + V₂)

b) Solve the equation (units are supressed just to manipulate the terms)

  • 18 = 10.5 + 0.35V₂

  • 0.35V₂ = 18 - 10.5 = 7.5

  • V₂ = 7.5 / 0.35 = 21.4 ml ← answer    
3 0
4 years ago
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