I suppose they can interpret the data differently.
I hope this helps!
Coriolis effect
That’s what I remember from whenever I was in that unit.
PART a)
By energy conservation we can say


divide whole equation by mass "m" and plug in all given data
![9.8(1.24) + \frac{1]{2}(1.7)^2 = 9.8(0) + \frac{1}{2}(v)^2](https://tex.z-dn.net/?f=9.8%281.24%29%20%2B%20%5Cfrac%7B1%5D%7B2%7D%281.7%29%5E2%20%20%3D%209.8%280%29%20%2B%20%5Cfrac%7B1%7D%7B2%7D%28v%29%5E2)

so gymnast will reach the floor with speed 5.21 m/s
PART b)
Now the gymnast bend her knees by 0.1 m and comes to rest
so here we will have



now the force on the gymnast will be


so during landing the force will be 6798.5 N