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3 years ago

12

How you do this resistor in circuit question?

1 answer:

lawyer [7]3 years ago

3 0

If Resistors are in series= The equivalent is the sum.

E.g R1 and R2 in series, R = R1 + R2.

If in Parallel, equivalent is Product/sum.

E.g If R1 and R2 in parallel, R = (R1*R2)/(R1+R2)

1.) 60 is parallel with 40 and both are then in series with 20.

60//40 = (60*40)/(60+40) = 2400/100 = 24

Now the 24 is in series with the 20

R = 24 + 20 = 44 ohms.

2.) 80 is in series with 40 and both are then in parallel with 40.

Solving the series, R = 80 + 40 =120.

Parallel: 120//40 = (120*40)/(120+40) = 4800/160 = 30
Equivalent Resistance = 30 ohms.

3.) 100 is in parallel with 100 and both are then in series with the parallel of 50 and 50.

The 1st parallel = (100*100)/(100+100) = 10000/200 = 50

The 2nd parallel = (50*50)/(50+50) = 2500/100 = 25.

Solving the series = 50 + 25 =75 ohms.

Cheers.

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2 years ago

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