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Rina8888 [55]
3 years ago
12

How you do this resistor in circuit question?

Physics
1 answer:
lawyer [7]3 years ago
3 0
If Resistors are in series= The equivalent is the sum.

E.g R1 and R2 in series,  R = R1 + R2.

If in Parallel, equivalent is Product/sum.

E.g If R1 and R2 in parallel,  R = (R1*R2)/(R1+R2)

1.)    60 is parallel with 40 and both are then in series with 20.

60//40   = (60*40)/(60+40) = 2400/100 = 24 

Now the 24 is in series with the 20 

R = 24 + 20 = 44 ohms.

2.)    80 is in series with 40 and both are then in parallel with 40.

Solving the series,  R = 80 + 40 =120.

Parallel:   120//40  =     (120*40)/(120+40) =  4800/160 = 30 
Equivalent Resistance = 30 ohms.

3.) 100 is in parallel with 100 and both are then in series with the parallel of 50 and 50.

The 1st parallel  =  (100*100)/(100+100) = 10000/200 = 50

The 2nd parallel  =  (50*50)/(50+50)  = 2500/100   = 25.

Solving the series  = 50 + 25 =75 ohms.

Cheers.
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The depth of focus achievable with those lenses is small.

Explanation:

A larger aperture makes it much harder to focus on more than one object. When using a telephoto lens (the ones the question is referring to), the depth of focus is very small. For example, using a telephoto lens to take a photo of a runner might get the runner in focus, but certainly not the track, or the audience behind them. If you look at photos, especially older photos, of Olympians in almost any sport you can see this.

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Answer:

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Explanation:

This question is tricky! We know the object moving to the left has a greater mass than the one moving to the right. We'd <em>assume</em> they would move to the left because the leftwards object has a greater mass, right?

Not. So. Fast.

We can solve for the objects' final velocity using the formula for momentum, m₁v₁ + m₂v₂ = (m₁ + m₂)v .

Now here's where the trap is sprung: <em>we don't think about the equation</em>. This shows that the final velocity of the objects and the direction depends on both the mass of the objects <em>and</em> their initial velocity.

Basically, what if the 3 kg object is moving at 1 m/s and the 4 kg object is moving at –0.5 m/s? The objects would move to the <em>right</em> after the collision!

Do we know the velocity of these objects? No, right?

That means we <em>can't</em> determine the direction of their motion <u>unless we know their initial, pre-collision velocity</u>. This question is tricky because we look at the 4 kg vs. 3 kg and automatically assume the 4 kg object would dictate the direction of motion. That's not true. It depends on velocity as well.

I hope this helps you! Have a great day!

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