1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alchen [17]
4 years ago
7

Ana poured equal amounts of water into four bowls. Then she put the bowls in the sun for different amounts of time. She recorded

the temperature of the water in each bowl after its time was up. Which bowl should have the warmest water?
Physics
2 answers:
sattari [20]4 years ago
4 0
The bowl which was out for the longest amount of time.
fiasKO [112]4 years ago
4 0

Answer:

Bowl 4

Explanation:

me big smart :)

You might be interested in
Two balls have their centers 2.0 m apart. One ball has a mass of m1 = 7.9 kg. The other has a mass of m2 = 6.1 kg. What is the g
maks197457 [2]

Answer:

3.036×10⁻¹⁰ N

Explanation:

From newton's law of universal gravitation,

F = Gm1m2/r² .............................. Equation 1

Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.

G = gravitational constant

Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²

Substituting into equation 1

F = 6.67×10⁻¹¹×7.9×6.1/2²

F = 321.427×10⁻¹¹/4

F = 30.36×10⁻¹¹

F = 3.036×10⁻¹⁰ N

Hence the force between the balls = 3.036×10⁻¹⁰ N

8 0
3 years ago
The surface air pressure on the planet mars is about 0.007 atm. if you were standing on mars, the surface air pressure would be
Lelu [443]
Surface air pressure is a consequence of the weight of the air acting on its surface. For example, if you are standing on Mars, the pressure around you is what you call the surface air pressure. Thus, that surface air pressure must be 0.007 atm.
5 0
3 years ago
Calculate the force of a particle with a net charge of 170 coulombs traveling at a speed of 135 meters/second perpendicular to t
amm1812

Answer:

F=1.14N j

Explanation:

The magnitude of the magnetic force over a charge in a constant magnetic field is given by the formula:

|\vec{F}|=|q\vec{v} \ X\ \vec{B}|=qvsin\theta  (|)

In this case v and B vectors are perpendicular between them. Furthermore the direction of the magnetic force is:

-i X k = +j

Finally, by replacing in (1) we obtain:

\vec{F}=(170C)(135\frac{m}{s})(5.0*10^{-5}T)=1.14N\ \hat{j}

hope this helps!

6 0
3 years ago
Read 2 more answers
IF U ANSWER I WILL MARK U BRAINLLIEST
goldfiish [28.3K]

Explanation:

a) Density is the amount of mass in a specific amount of volume

b) Some substances are less dense than water so will float and vice versa

c) The wooden plank has less density than water due to having larger volume and vice versa with the wooden block since volume and density are inversely proportional

II) (a) They are all metals

(b) water -> Compound

oxygen -> Element

Gold-> Element

Salt-> Compound

6 0
3 years ago
Read 2 more answers
 1–Find the components of each vector
navik [9.2K]

Answer:

ANSWERS ARE 100 % correct

Explanation:

trust me

7 0
3 years ago
Other questions:
  • TEST HELP PLEASE!! WILL GIVE MEDAL TO BEST ANSWER!!
    9·2 answers
  • Can anyone help me with any parts in question number 1: parallel circuit?
    6·1 answer
  • How to find answers to webassign questions online
    6·1 answer
  • 009 10.0 points
    6·2 answers
  • The motion of an object thrown at an angle is projectile motion. True or false
    6·2 answers
  • A labor push a crate through 12m and 720 J of work .The magnitude of force was
    5·1 answer
  • A 140-kg box is being lowered at constant velocity. A rope is attached to the top of the box, and Jimmy is slightly supporting t
    10·1 answer
  • What is an alloy?
    11·1 answer
  • The greater the mass of an object?<br> I’ll give brainliest!*
    13·1 answer
  • Which two changes would decrease the electric force between two charged
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!