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3 years ago

Which scientist discovered the laws that determine the motion of a spring?

Physics

1 answer:

Kruka [31]3 years ago

7 0

Answer: Robert Hooke

Explanation: Hooke's law, law of elasticity discovered by the English scientist Robert Hooke in 1660, which states that, for relatively small deformations of an object, the displacement or size of the deformation is directly proportional to the deforming force or load.

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What is the idea behind the law of multiple proportions?

Akimi4 [234]

Answer:

The law of multiple proportions states that when two elements can combine in different ratios to form different compounds, the masses of the element combining with the fixed mass of another element result in whole number ratios. This shows that the law of multiple proportions is followed

Explanation:

5 0

4 years ago

Two locomotives approach each other on parallel track. Each has speed of 95 km/h with respect to the ground.If they are initiall

irinina [24]

Answer:

It will take 2.68 minutes for them to reach each other.

Explanation:

We use the two following kinematic equations, making the final position the same (for the moment they meet each other):

locomotive 1 --> $x_f=v*t$

locomotive 2 --> $x_f=8.5\,-\,v*t$

we make the two xf equal, and solve for the time (t) using v = 95 km/h:

$95*t=8.5-95*t\\2*95*t=8.5\\t=8.5/(190)\\t = 0.0447\,\,hours$

converting the hours into minutes by multiplying this value times 60;

t = 2.68 minutes

3 0

3 years ago

A helicopter goes straight up 500m from a landing pad. It then goes north 20m. Then it goes down 452m. a) What is the displaceme

gavmur [86]

Answer:

x-component $20 \ m$

y-component $500 - 452 = 48 \ m$

Magnitude $d = 52 \ m$

direction is $\theta = 67.4^o$

Explanation:

From the question we are told that

The first vertical distance is $y_1 = 500 \ m$

The first horizontal distance is $x = 20 \ m$

The second vertical distance is $y_2 = 452 \ m$

Generally the displacement is

x-component $20 \ m$

y-component $500 - 452 = 48 \ m$

Generally the helicopters displacement is mathematically evaluated as

$d = \sqrt{ x- component ^2 + y- component ^2 }$

$d = \sqrt{ 20t ^2 + 48 ^2 }$

$d = 52 \ m$

The direction is the angle the displacement of the helicopter makes with the horizontal which is mathematically evaluated as

$\theta = tan ^{-1}[ \frac{48}{20}]$

=> $\theta = tan ^{-1}[ 2.4 ]$

=> $\theta = 67.4^o$

3 0

3 years ago

A person walks from her home at position O to position F by taking a path that is comprised of three displacement vectors travel

lidiya [134]

Answer:

Explanation:

A = 155 m at 25° North of west

B = 92 m due north

C = 64.7 m at an angle 50° East of north

Write the displacements in the vector form

$\overrightarrow{A} = 155\left ( Cos25\widehat{i}-Sin25\widehat{j} \right )$

$\overrightarrow{A}=140.5\widehat{i}-65.5\widehat{j}$

$\overrightarrow{B}=92\widehat{j}$

$\overrightarrow{C} = 64.7\left ( Cos50\widehat{i}+Sin50\widehat{j} \right )$

$\overrightarrow{C} = 41.6\widehat{i}+49.6\widehat{j}$

(a)

$\overrightarrow{A}.\overrightarrow{C}=\left ( 140.5\widehat{i}-65.5\widehat{j} \right ).\left ( 41.6\widehat{i}+49.5\widehat{j} \right )$

$\overrightarrow{A}.\overrightarrow{C} = 2602.55$

(b)

$\overrightarrow{A}\times \overrightarrow{C}=\left ( 140.5\widehat{i}-65.5\widehat{j} \right )\times \left ( 41.6\widehat{i}+49.5\widehat{j} \right )$

$\overrightarrow{A}\times \overrightarrow{C}=9679.55 \widehat{k}$

4 0

3 years ago

If the strength of the magnetic field at A is 200 units and the strength of the magnetic field at B is 50 units, what is the dis

Whitepunk [10]

A is the answer!!!!!!!!!!!!!!!!!!

5 0

3 years ago