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3 years ago

12

Which characteristic of the gas giants decreases with increasing distance from the sun?

2 answers:

hodyreva [135]3 years ago

7 0

Equator diameter and Number of moons. So both a and c would be the answer :)

anyanavicka [17]3 years ago

4 0

Gas giant are plants with mass 10 times bigger than the mass of the Earth. They are also called outer planets. There are four gas giant planets in our solar system: Jupiter, Saturn, Uranus and Neptune. The farther away from the Sun they are (the distance from the Sun is increased) the longer they orbit the Sun because of the great distance.

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Earth's atmosphere is made up of mostly nitrogen (78%) and oxygen (21%); however, there are other gases in smaller amounts, like

pishuonlain [190]

Answer:

the temperature would increase globally because carbon dioxde contributes to global warming increase the temperature of the earth

Explanation:

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5 0

3 years ago

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At which of the above boundries is sea floor destroyed

Slav-nsk [51]

The continental crust
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7 0

3 years ago

On a planet where g = 10.0 m/s2 and air resistance is negligible, a sled is at rest on a rough inclined hill rising at 30°. The

Cloud [144]

Answer:

Explanation:

a is the acceleration

μ is the coefficient of friction

Acceleration of the object is given by

$a = g (\sin \theta -\mu \cos \theta)\\\\=10( \sin 30 - 0.4 \cos 30)\\\\=10(0.5-0.3464)\\\\=1.54m/s^2$

Velocity at the bottom

$v^2=u^2+2as\\\\u=0\\\\v^2=2as\\\\=2*1.54*8\\\\=24.576\\\\v=4.96m/s$

after travelling 4m , its velocity becomes 0

$a=\frac{v^2-u^2}{2s}$

$a=\frac{0-u^2}{2s}$

$a=\frac{-(-4.96)^2}{2*4} \\\\=-3.075m/s^2$

Coefficient of kinetic friction

μ = F/N

$=\frac{ma}{mg} \\\\=\frac{3.075}{10} \\\\=0.31$

Therefore, the Coefficient of kinetic friction is 0.31

8 0

2 years ago

Read 2 more answers

A horizontal spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor. The

Damm [24]

Answer:

ugmd = 1/2 kx²

d = (1/2 kx²) / (ugm)

= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)

= 7.4 m

ugmd = 1/2 mv²

v = √2ugd

= √(2(0.23)(9.81 m/s²)(7.4 m)

= 5.8 m/s

Explanation:

3 0

3 years ago

How much force is needed to accelerate an object of mass 90 kg at a rate of 1.2 m/s2

soldier1979 [14.2K]

∑F = ma = (90 kg)(1.2 m/s²) = 108 N = 100 N (1 significant digit)

3 0

3 years ago

Read 2 more answers