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kondaur [170]
4 years ago
7

an 85 kg object is moving at a constant speed of 15 m/s in a circular path which has a radius of 20 meters. what centripetal for

ces is exerted on the body
Physics
1 answer:
sasho [114]4 years ago
5 0
Fc=mv^2/r
Fc= 85kg*(15m/s)^2/(20) = 956.25N

hope this helps! Thank you!
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In a typical badminton swing the racket is in contact with the birdy for about 0.0010 seconds. If the 0.045kg birdy acquires a s
zepelin [54]

Answer:

3015 N

Explanation:

From Newton's second law, we know that;

F.t = mv

F = force on the ball= ?

m= mass of the ball

v= velocity

F= mv/t

F= 0.045 × 67/0.0010

F= 3.015/0.0010

F= 3015 N

3 0
3 years ago
A parallel-plate capacitor is held at a potential difference of 250 V. A proton is fired toward a small hole in the negative pla
MissTica

Answer:

The speed of proton when it emerges through the hole in the positive plate is 2.05\times 10^5\ m/s.

Explanation:

Given that,

A parallel-plate capacitor is held at a potential difference of 250 V.

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We need to find the speed when it emerges through the hole in the positive plate. It can be calculated using the conservation of energy as :

qV=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2\\\\1.6\times10^{-19}\times250=\dfrac{1}{2}mv^2-\frac{1}{2}\cdot1.67\times10^{-27}\cdot(3\times10^{5})^{2}\\\\\dfrac{1}{2}mv^2=3.515\cdot10^{-17}\\\\v=\sqrt{\dfrac{3.515\cdot10^{-17}\cdot2}{1.67\times10^{-27}}}\\\\v=2.05\times 10^5\ m/s

So, the speed of proton when it emerges through the hole in the positive plate is 2.05\times 10^5\ m/s.

5 0
3 years ago
Two circular loops of wire, each containing a single turn, have the same radius of 5.10 cm and a common center. The planes of th
Fofino [41]

Explanation:

Below is an attachment containing the solution.

8 0
3 years ago
Recall that the blocks can only move along the x axis. the x components of their velocities at a certain moment are v1x and v2x.
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The center of mass is given with this formula:
x_c=\frac{\sum_{n=1}^{n=i}m_ix_i}{M}
Velocity is:
v=\frac{dv}{dt}
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\frac{dx_c}{dt}=\frac{\sum_{n=1}^{n=i}d(m_ix_i)}{Mdt}\\
v_c=\frac{\sum_{n=1}^{n=i}p_i}{M}\\
In our case it is:
v_{xc}=\frac{m_1v_{x1}+m_2v_{x2}}{m_1+m_2}
 
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4 years ago
When objects are forced to vibrate ( like when dropped onto a hard surface), they will do so at their
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They'll vibrate at their characteristic resonant frequency. That depends on the material the object is made of and its shape.


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