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kondaur [170]
3 years ago
7

an 85 kg object is moving at a constant speed of 15 m/s in a circular path which has a radius of 20 meters. what centripetal for

ces is exerted on the body
Physics
1 answer:
sasho [114]3 years ago
5 0
Fc=mv^2/r
Fc= 85kg*(15m/s)^2/(20) = 956.25N

hope this helps! Thank you!
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A 10 kg ball is swung in a horizontal circle at the end of a 2 - m rope over a persons head. The ball makes 30 revolutions per m
steposvetlana [31]

Answer : T = 2 s and Speed = 6.28 m/s.

Explanation :

It is given that,

Mass of the ball, m = 10 kg

Radius of the circle, r = 2 m

The ball makes 30 revolutions per minute. So, frequency is given by :

f=\dfrac{30}{60\ s}

f=\dfrac{1}{2}\ Hz

We know that time period is defined as the reciprocal of frequency i.e.

T=\dfrac{1}{f}

T=2\ s

So, the time period for the ball to go around once is 2 s.

Now, speed is defined as distance travelled per unit time. Distance travelled by ball in circular path is equal to the circumference of the circle.

Speed =\dfrac{distance}{time}

S=\dfrac{2\pi r}{T}

S=\dfrac{2\times 3.14\times 2\ m}{2\ s}

S=6.28\ m/s

Speed of the ball is 6.28 m/s.

8 0
3 years ago
How many grams does 15.58 L of gasoline weigh? Gasoline has a density of 0.74 g/mL
Korolek [52]

We are given volume of gasoline = 15.58 L and

Density = 0.74 g/mL.

Density is given in grams(g) per milliliter (mL). So, we need to convert given volume in mL also.

We know, 1 litre = 1000 milliliters

Therefore, 15.58 L = 15.58 * 1000 mL = 15580 mL

We could rewrite,

Volume of gasoline = 15580 mL.

Formula for density is..

Density (ρ)= \frac{Mass}{ Volume}

Plugging values in formula,

0.74  g/mL = \frac{Mass}{15580 \ mL}

Muliplying both sides by 15580.

0.74 g/mL * 15580mL =\frac{Mass}{15580 \ mL} * 15580mL

11529.2g = mass.

Therefore, 11529.2g grams does 15.58 L of gasoline weigh.




5 0
3 years ago
Over a time interval of 1.71 years, the velocity of a planet orbiting a distant star reverses direction, changing from +17.3 km/
lutik1710 [3]

Answer:

a)40100m/s

b)-4.348x10^- m/s^2

Explanation:

to calculate the change in the planet's velocity we have to rest the speeds

ΔV=-22.8-17.3=-40.1km/s=40100m/s

A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

Vf=Vo+a.t  (1)\\\\

{Vf^{2}-Vo^2}/{2.a} =X(2)\\\\

X=Xo+ VoT+0.5at^{2}    (3)\\

Where

Vf = final speed

Vo = Initial speed

T = time

A = acceleration

X = displacement

In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve

for this problem we have to convert the time interval ins seconds, we know that a year has 53926560s

t=1.71years=53926560*1.71=92214417.6

then we can use the ecuation number 1 to calculate the aceleration

Vf=-22.8km/s

Vo=17.3km/s

Vf=Vo+at

a=(vf-vo)/t

a=(-22.8-17.3)/92214417.6

a=-4.348x10^-7 km/s^2=-4.348x10^- m/s^2

4 0
3 years ago
If a team pulls with a combined force of 4 newtons on an airplace with a mass of 36 kilograms,what is the acceleration of the ai
MatroZZZ [7]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                    \boxed{F=ma}

                                                 <u>Δ   Being   Δ</u>

                                                F = Force = 4 N

                                              m = mass = 36 kg

                                             a = Aceleration = ?

⇒ Let's replace according the formula:

\boxed{4\ N = 36\ kg * \textbf{a}}

⇒ Clear acceleration and resolve it:

\boxed{\textbf{a}=0,111\ m/s^{2}}}

Result:

The aceleration is of <u>0,111 meters per second squared (m/s²)</u>

Good Luck!!

5 0
2 years ago
• What value is used to identify each element in the periodic table?​
bearhunter [10]

Answer:

protons

Explanation:

5 0
2 years ago
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