Answer:
Part A: impossible
Part B: Either equal or blue
Part C: 9 green and 2 blue were added
Step-by-step explanation:
Part A:
The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.
Part B:
I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.
Part C:
The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.
I hope this helps and please mark me as brainliest!
X=-1/29 it’s divided the 1 /29
Answer:
It depends on what shape you have. Here are some formulas for different shapes.
Step-by-step explanation:
Rectangular prism: 2lw + 2lh + 2wh
Cylinder: 2 pi <em>r</em>² + 2 pi <em>rh</em>
Sphere: 4 pi <em>r</em>²
Cone: pi <em>r</em>² + pi <em>rl</em>
Square-based pyrimid: 1/2<em>lp</em> +<em>B</em>
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I hope this helps!
27.98ft
You can get this by using the tangent formula. The answer exactly expressed is 60tan25.
Answer: 10.703%
Step-by-step explanation:
Let minimum height of the tallest 25% of young women be M.
Let Q be the random variable which denotes the height of young women.
Therefore, Q – N(64,2.70)
Now, P(Q˂M) = 1-0.25
i.e. P[(Q-64)/2.7 ˂ (M-64)/2.7] = 0.75
I.e. ф-1 [(M-64)/2.7] = 0.75 i.e. (M-64)/2.7 = ф-1 (0.75) = 0.675 i.e. M = 65.8198 inches
Let R be the random variable denoting the height of young men
Therefore, R – N (69.3, 2.8)
i.e. (R-69.3)/2.8 – N(0,1)
therefore the probability required = P(R ˂65.8198) = P[(R-69.3)/2.8 ˂ (65.8198 – 69.3)/2.8]
this gives P[(R-69.3)/2.8 ˂] = ф (-1.2429) = 0.107033
From this, the percentage of young men shorter than the shortest amongst the tallest 25% of young women is 10.703%
