A year has two semesters, then
n = 2<span>v(t)=p<span><span>(<span>1+<span>r/2</span></span>)</span><span>2t
</span></span></span><span>
3875.79 = 1900∗<span><span>(<span>1+(<span>0.04/2)</span></span>)^</span><span>2t
</span></span></span><span>
2.0398895 = <span><span>(<span>1+<span>0.042</span></span>)^</span><span>2t
</span></span></span>Apply natural logarithm on both sides
<span>ln(2.0398895) = ln<span>[<span><span>(<span>1+<span>0.042</span></span>)^</span><span>2t</span></span>]
Then simplify,
</span></span><span>0.712896 = 2t∗ln(1.02)
</span><span>t = <span>0.712896 / (<span>2∗ln(1.02))
</span></span></span><span><span>
t=18 years
I hope my answer helped you. Have a nice day!</span></span>
Answer:
Assemblage.
Explanation:
In Real estate, putting together two or more parcels of land to make a large piece is called assemblage. The main purpose of assemblage is to increase the price of parcels of land by combining them together rather than selling them individually as a single unit.
<em>For instance, a real estate agent may purchase two (5) parcels of land each worth $50,000 (2 × $50,000). When he assembles them, the new single parcel of land is worth $150,000. </em>
Answer:
B. may incorporate in any state it chooses.
Explanation:
Answer:
1. 2006 Student
2. 4400 pesos left
Explanation:
If each student had $500 to spend and In 2002, the exchange rate of MXN/USD (Mexican pesos to U.S. dollars) was 9 and In 2006, the exchange rate was 11.
If the hotel room in Guadalajara cost 200 pesos per night in 2002 and 220 pesos in 2006 and each student spent five nights in a hotel, which student had more pesos left over:
Student A - 2002
Spent 5 nights x 200 pesos = 1000 pesos
Total pesos = $500 x 9 = 4500 pesos
Pesos left = 4500 - 1000 = 3500 pesos
Student B - 2006
Spent 5 nights x 220 pesos = 1100 pesos
Total pesos = $500 x 11 = 5500 pesos
Pesos left = 5500 - 1100 = 4400 pesos
