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2 years ago

Determine the kinetic energy of a 625-kg roller coaster car that is moving with a speed of 10 m/s.

2 answers:

6 0

The equation for kinetic energy is:

KE = 1/2 x mass x (velocity)^2

Mass = 625
Velocity = 10

Substitute the values into the equation.

KE = 1/2 x 625 x (10)^2

KE = 1/2 x 625 x 100

KE = 31250 joules

abruzzese [7]2 years ago

5 0

Hi there!

Kinetic energy can be calculated using the following:

$\large\boxed{KE = \frac{1}{2}mv^2}}$

Where:

KE = Kinetic energy (J)

m = mass (kg)

v = velocity (m/s)

Plug in the given values:

$KE = \frac{1}{2}(625)(10^2) = \boxed{31250J}$

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Suppose astronomers built a 150-meter telescope. how much greater would its light-collecting area be than that of the 10-meter k

Dennis_Churaev [7]

Almost all telescopes have a circular mirror. The area of a circle is proportional to $r^2$ where $r$ is the radius of the circle, the constant of proportionality being $4\pi$
$S =4\pi r^2$
Therefore the area of 150 meter telescope would be
$S_1/S_2=(r_1/r_2)^2 =(75/5)^2 =15^2=225$
times bigger than the area of the smaller (10 meter) telescope.

6 0

3 years ago

What will the stopping distance be for a 2,000-kg car if -2,000 N of force are applied when the car is traveling 20 m/s?

astraxan [27]

Answer is B- 200 m

Given:

m (mass of the car) = 2000 Kg

F = -2000 N

u(initial velocity)= 20 m/s.

v(final velocity)= 0.

Now we know that

F= ma

Where F is the force exerted on the object

m is the mass of the object

a is the acceleration of the object

Substituting the given values

-2000 = 2000 × a

a = -1 m/s∧2

Consider the equation

v=u +at

where v is the initial velocity

u is the initial velocity

a is the acceleration

t is the time

0= 20 -t

t=20 secs

s = ut +1/2(at∧2)

where s is the displacement of the object

u is the initial velocity

t is the time

v is the final velocity

a is the acceleration

s= 20 ×20 +(-1×20×20)/2

s= 200 m

3 0

3 years ago

Read 2 more answers

1. Boyle's law relates the pressure of a gas to its

KIM [24]

Answer:

volume is the correct answer

Explanation:

7 0

2 years ago

A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit

likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density $\mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m$

Tension in the wire T = 25 N

Frequency f = 120 Hz

So angular frequency $\omega =2\pi f=2\times 3.14\times 120=753.6rad/sec$

And amplitude A = 1.6 mm = 0.0016 m

We have to find the generated power

Power is given by $P=\frac{1}{2}\sqrt{\mu T}\omega ^2A^2=\frac{1}{2}\times \sqrt{0.0031\times 25}\times 753.6^2\times 0.0016^2=0.2023watt$

From the relation we can see that power $P\ \propto\ A^2$

So if amplitude is halved then power will be $\frac{1}{4}$ times

So power will be equal to $\frac{0.2023}{2}=0.0505watt$

4 0

3 years ago

How much force is needed to accelerate a bicycle and rider with a total mass of 50 kg at a rate of 2.0 m/s2 ?

True [87]

Answer:

The answer is D 100 newton

Explanation:

2.0m/s2 is d acceleration while the 50kg is the mass. Force = mass x acceleration. So f=50x2.so force is 100 newton

8 0

3 years ago