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2 years ago

Determine the kinetic energy of a 625-kg roller coaster car that is moving with a speed of 10 m/s.

2 answers:

6 0

The equation for kinetic energy is:

KE = 1/2 x mass x (velocity)^2

Mass = 625
Velocity = 10

Substitute the values into the equation.

KE = 1/2 x 625 x (10)^2

KE = 1/2 x 625 x 100

KE = 31250 joules

abruzzese [7]2 years ago

5 0

Hi there!

Kinetic energy can be calculated using the following:

$\large\boxed{KE = \frac{1}{2}mv^2}}$

Where:

KE = Kinetic energy (J)

m = mass (kg)

v = velocity (m/s)

Plug in the given values:

$KE = \frac{1}{2}(625)(10^2) = \boxed{31250J}$

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A key lime pie in a 10.00 inch diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the

juin [17]

Answer:

The angular distance in revolution is $revolution = 3.439 \ revolution$

The angular distance in radians is $\theta_{rad}= 21.6 \ radians$

The angular distance in degrees is $\theta =1238.04^o$

The angular size is $Z = \frac{2}{9} \pi \ radians$

Explanation:

From the question we are told that

The diameter is $d = 10 \ inches$

The distance moved by the rim is $D = 108 \ inches$

Generally the circumference of the pie plate is mathematically represented as

$C = \pi d$

Substituting the values

$C = 10 *3.142$

$= 31.42 \ inches$

The number resolution carried out by the pie plate is evaluated as

$revolution = \frac{D}{C}$

Substituting value

$revolution = \frac{108}{31.4}$

$revolution = 3.439 \ revolution$

The angular distance $\theta_{rad}$ is mathematically evaluated as

$\theta_{rad} = \frac{D}{r}$

Where r is the radius which is mathematically evaluated as

$r = \frac{d}{2} = \frac{10}{2} = 5 \ inches$

Substituting this into the equation for angular distance

$\theta_{rad} = \frac{108}{5}$

$\theta_{rad}= 21.6 \ radians$

The angular distance traveled in degrees is

$\theta = 3.439 *360$

$\theta =1238.04^o$

When the pie is cut into 9 equal parts

The angular size would be mathematically evaluated as

$Z = \frac{2\pi}{9}$

$Z = \frac{2}{9} \pi \ radians$

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4 years ago

Which energy transformation occurs in the core of a nuclear reactor?

Nataliya [291]

It's either A or B because it starts off as nuclear energy.

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3 years ago

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The density of seawater plays a vital role in causing ocean currents and circulating heat because of the fact that dense water sinks below less dense. long story short, seawater is the problem because its denser than pure water.

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3 years ago

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What is the work function of cadmium metal if light with = 9.85×1014hz is necessary to eject electrons?

Alika [10]

We use the Planck’s formula:

E = hv

where,

E = energy, h = planck’s constant = 6.6x10^-34 J s, v = frequency in Hz (Hz = 1 / s)

Subsituting the values to find for E:

E = (6.6×10^-34 J s) * 9.85×10^14 / s

E = 6.5x10^-19 J

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3 years ago

Gold has a density of 19.3 grams per cubic centimeter. what is the density of gold in metric tons per cubic meter?

valina [46]

In order to determine this, we will first need some conversions. We will need to convert metric tons and grams into one another and also cubic centimeters to cubic meters into one another.

1 metric ton = 1000 kg

1 kg = 1000 grams

1 metric ton = 10⁶ grams

So 10⁶ grams / metric ton

1 meter = 100 cm
1 m³ = (100)³ cm³
1 m³ = 10⁶ cm³

So 10⁶ cm⁶ / m³

Now, we manipulate the given value:

(19.3 grams / cm³) * (1 metric ton / 10⁶ grams) * (10⁶ cm³ / m³)
= 19.3 metric tons / m³

The density of gold is 19.3 metric tons meter meter cubed.

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3 years ago